What type of weather would be in the middle of the picture, where the barometric pressure is 1000 millibars?

What are you experiencing if you close your eyes and feel as if you are not moving

vlabodo [156]

Well i would feel i am moving i also would be scared if i didnt know i was moving even with my eyes closed

8 0

4 years ago

In this lab, you will observe current induced through the interaction of a magnet and wire coil, while changing one property of

Brrunno [24]

Answer:

How does magnet polarity affect the current flowing in a loop of wire?

Explanation:

5 0

3 years ago

Read 2 more answers

If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu

zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² = 236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 = 0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245 = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient is 0.26

4 0

3 years ago

Read 2 more answers

A golf ball is hit horizontally off the edge of a 30 m high cliff and lands a distance of 25 m from the edge of the cliff. What

Ratling [72]

Answer:

V₀y = 0 m/s

t = 2.47 s

V₀ₓ = 61.86 m/s

Vₓ = 61.86 m/s

Explanation:

Since, the ball is hit horizontally, there is no vertical component of velocity at initial point. So, the initial vertical velocity (V₀y) will beL

V₀y = 0 m/s

For the initial vertical velocity of golf ball we consider the vertical motion and apply 2nd equation of motion:

Y = V₀y*t + (0.5)gt²

where,

Y = Height = 30 m

g = 9.8 m/s²

t = time to hit the ground = ?

Therefore,

30 m = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

t² = 30 m/4.9 m/s²

t = √6.122 s²

t = 2.47 s

For initial vertical velocity we analyze the horizontal motion of the ball. We neglect the frictional effects in horizontal motion thus the speed remains uniform. Hence,

V₀ₓ = Xt

where,

V₀ₓ = Initial vertical Velocity = ?

X = Horizontal Distance = 25 m

Therefore,

V₀ₓ = (25 m)(2.47 s)

V₀ₓ = 61.86 m/s

Due, to uniform motion in horizontal direction:

Final Vertical Velocity = Vₓ = V₀ₓ

Vₓ = 61.86 m/s

4 0

3 years ago

A 2.5 kg steel gasoline tank can holds 20.0 L of gasoline when full. What is the average density (in Kg/m^3) of the full gas can

yarga [219]

Answer:

$D=792.3\ kg/m^3$

Explanation:

Average Density

The density of an object of mass m and volume V is

$\displaystyle D=\frac{m}{V}$

If we know the density and the volume occupied by the object, the mass can be computed as

$m=D.V$

The tank can hold 20 L of gasoline when full. Converting to cubic meters

$V_g=20*0.001=0.02\ m^3$

That's the volume of the gasoline it contains. Knowing the density of the gasoline, we get the mass of gasoline.

$m_g=680*0.02=13.6\ kg$

To know the total mass of both, we add the 2.5 kg of the tank

$m=m_t+m_g=13.6+2.5=16.1\ kg$

The volume of the tank is computed solving for V

$\displaystyle V=\frac{m}{D}$

$\displaystyle V_t=\frac{2.5}{7800}=3.205\times 10^{-4}\ m^3$

The total volume is

$V=V_g+V_t=0.02+3.205\times 10^{-4}=0.0203\ m^3$

The average density is

$\displaystyle D=\frac{16.1}{0.0203}$

$\boxed{D=792.3\ kg/m^3}$

7 0

3 years ago