In air, you'd call it air resistance, pilots call it drag. In water, some call it
water resistance, or just plain drag.
Whatever it's called, it's the friction between the object and the fluid, plus
the force needed to push the fluid out of the way to let the object get through.
Answer:
Explanation:
Given
mass of block 
at 
displacement is 
velocity 
acceleration 
suppose
is the general equation of SHM
where A=amplitude
=natural frequency of oscillation
therefore velocity and acceleration is given by


for t=0



divide 1 and 3 we get


Now square and 1 and 2 we get



They travel like waves. Just throw rock at lake you will see wave. When it bumps to barrier barrier reflects some part of it . Not like a line lika a wave
Evaporated water changes form into gas
Answer:
To maintain enough time to prevent a collision, a system operating in air traffic where aircraft speed does not
fall below 100 km/h (most medium-sized UAVs and GA aircraft) will need to be able to detect obstacles which
subtend an arc-width of as small as 0.125 mra