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3 years ago

PLEASE HELP GEOMETRY

Mathematics

2 answers:

Liono4ka [1.6K]3 years ago

5 0

The distance between any two points is the so-called distance formula which is an extension of the Pythagorean Theorem:

d^2=(x2-x1)^2+(y2-y1)^2, where (x1,y1) and (x2,x1) are two points.

In this case:

d^2=(3--6)^2+(5--6)^2

d^2=9^2+11^2

d^2=81+121

d^2=202

d=√202 units

d≈14.21 units (to the nearest hundredth of a unit)

Taya2010 [7]3 years ago

4 0

The distance formula is sqrt((x1-x2)^2 + (y1-y2)^2), therefore (3-(-6))^2 = 9^2 and (5 -(-6))^2 = 11^2 so 121 + 81 = sqrt(202), this converted to decimal is ~14.21, so D.

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Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.

f(a)=4-2a+6 $a^{2}$ (By just putting x=a).

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[f(a+h)-f(a)]/h=[ $6a^{2} +6h^{2}-2a-2h+12ah$ -(4-2a+6 $a^{2}$ )]/h

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