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lukranit [14]
3 years ago
14

Identify and explain which ball most likely had the greatest speed.

Physics
1 answer:
deff fn [24]3 years ago
4 0
Y, bc the height of the bounce back is higher than x
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How would a person who believes in the geocentric solar
Gemiola [76]
Id say A because the geocentric model is where the earth is at the center of the universe and all other planets, suns, stars, and moons are revolving around it
4 0
3 years ago
The coefficent of static friction between the floor of a truck and a box resting on it is 0.38. The truck is traveling at 87.9 k
nekit [7.7K]

Answer:

d=79.9m

Explanation:

From the question we are told that:

coefficient of static friction \mu=0.38

Velocity v=87.9=>24.41667m/s

Generally the equation for Conservation of energy is mathematically given by

 \mu*mgd = 0.5 m v^2

 d=\frac{0.5*24.42^2}{0.38*9.8}

 d=79.9m

3 0
3 years ago
What is the acceleration of a Porsche that can go from 15 mi/hr to 75 mi/hr in 4 seconds?
Elodia [21]

Hi there!

Acceleration = change in velocity / change in time = Δv/Δt

Thus:

a = (75 - 15)/4 = 60/4 = 15 mi/hr²

8 0
2 years ago
Read 2 more answers
Is a lawn mower a drag force OR friction force
dalvyx [7]

Answer:

Pretty sure it's friction force

Explanation:

Because you pretty much just push it I guess

8 0
3 years ago
A soccer ball is kicked from the ground with an initial speed v at an upward angle θ. A player a distance d away in the directio
Nady [450]

Answer:

The speed of player is given by

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

Explanation:

The time of flight for a projectile motion is given by

T=\frac{2vsin\alpha }{g}    (i)

where t is the time of flight, v is the initial speed, and α is the angle.

Now the person must also reach the impact point of ball in the same time as above.

Now the total distance D the player needs to cover is basically R horizontal range of projectile minus the distance d, range R is given by,

R=\frac{2v^{2} sin2\alpha }{g}

Now the distance the player must cover is given by

D= R-d

D= \frac{2v^{2} sin2\alpha }{g}  - d

 

D=\frac{2v^{2}sin2\alpha-gd}{g}  (ii)

Now the average speed of player is given by

V=\frac{D}{T}   (iii)

Replacing the values of D and T from eq. (i) and (ii) in eq. (iii).

V=\frac{\frac{2v^{2} sin2\alpha-gd }{g}}{\frac{2vsin\alpha }{g} }

V=\frac{2v^{2} 2sin\alpha.cos\alpha-gd }{2vsin\alpha}

3 0
3 years ago
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