<span>a crack across rock layers caused by moving plates
molten rock - fault (a fault is a rupture or scission in a block of rocks that allows both parts from the scission to slide over each other)
</span><span>horizontal intrusion - sill (a sill is a mass of igneous rock that intruded horizontally and laterally through rock layers already existent)
</span><span>vertical intrusion - d(y)ke (a d(y)ke is also a mass of igneous rock, but this time that intruded vertically across rock layers, many times through an already existing crack)
</span><span>natural, upward movement of rock layers - uplift (uplift is a geological process in which a portion of the Earth's crust is elevated from its original position due to plate tectonics)</span>
Answer:
B
Explanation:
Digestive as it has enzymes that turn food into energy.
The talk test can be used to measure the <u>intensity of an activity</u>
<u>Option: B</u>
<u>Explanation:</u>
The talk test is usually used to measure the intensity of a particular activity when a person talks during that activity. This is mostly used in cardiovascular patients to measure the intensity of the exercise.
For example, when a person can talk during exercising, it means that he is able to use the oxygen to create energy for the muscles. i.e he will be in aerobic state. Incase, he is not able to talk any more during his exercise, it means that the breathing rate has reached a particular ventilatory threshold.
So now the body is creating energy from the stored system such as muscle glucose and creatine. Thus this talk test helps to determine in which way your body creates energy, aerobic or non aerobic.
Answer:
0.275 m/s²
Explanation:
The acceleration of an object is defined as the change in velocity over the change in time.
We are given the initial velocity, 0.75 m/s. The final velocity of the user in question is 3.5 m/s.
The time it takes for us to catch the train is 10 seconds. Using these variables, let's substitute into our equation.
- a = (3.5 - 0.75)/10
- a = 2.75/10
- a = 0.275 m/s²
Our acceleration over that time was 0.275 m/s² in order to catch the train.
