He’s and heists sijsnsns shamans
Three of these are strong electrolytes:
- HCl (Hydrochloric acid)
- HNO3 (Nitric acid)
- NaOH (Sodium hydroxide)
Two of these are Weak electrolytes:
- HF (Hydrogen fluoride)
- HC2H3O2 (Acetic acid)
And the other two are Non-electrolytes:
- C6H12O6 (Glucose)
- C2H5OH (Ethanol)
Your answer would be D. Transpiration
Answer:
f = 55mm, h ’= -9.89 cm
f = 200 mm, h ’= 42.5 cm
Explanation:
For this exercise let's start by finding the distance to the image, using the equation of the constructor

where f is the focal length, p and q are the distances to the object and image, respectively
lens with f₁ = 55mm = 0.55cm
=
= 1.718
q₁ = 0.582 m
lens with f₂ = 200mm = 2m
=
= 0.4
q₂ = 2.5 m
the magnification of a lens is given by
m =
h ’=
let's calculate for each lens
f = 55mm
h '= - 0.582 / 10 1.7
h ’= 0.0989 m
h ’= -9.89 cm
f = 200 mm
h '= - 2.5 / 10 1.7
h ’= -0.425 m
h ’= 42.5 cm
The negative sign indicates that the image is real and inverted
Answer:
W = 3.4x0³ J.
Explanation:
The work done by the man is given by the following equation:
(1)
<em>where W: is the work, Ft is the total force and d: is the displacement = 4.25 m.</em>
We need to find first the total force Ft, which is:

<em>where Fm: is the force exerted by the man = 535 N, W: is the weight = m*g*sin(θ), m: is the mass of the man, g: is the gravitational acceleration = 9.81 m/s², and θ: is the angle = 20.0°. </em>

Hence, the work is:
Therefore, the work done by the man is 3.4x10³ J.
I hope it helps you!