Answer:
a, V = 65.6V
b. V = 131.0V
C. V = 131.0V
Explanation:
Given
Total electric charge 
distributed uniform at surface of metal sphere where radius is R = 24cm
R = 24cm = 0.024m
we have to find potential at different distance
a. r = 48cm = 0.048m
b. r = 24cm = 0.024m
c. r = 12cm = 0.012m
a. <u>solution</u>
Here the distance r is grater then R,we can get the potential outside of sphere
now we plug the value <em>q</em> and <em>r</em> in potential<em> v</em>
=65.6V
b.<u>solution</u>
Here distane r is the same from radius R, so we can get potential inside sphere
Now we plug the value of R and q
3.<u>solution</u>
Inside sphere electric feild is zero.so potential is the same every point inside sphere and equal potential on the surface
Answer:
Magnitude of C= 
Angle=arctan(Ay+By/Ax+Bx)
Explanation:
Let
A = Axi + Ayj
B = Bxi + Byj
where i and j are unit vectors in the direction of x and y axes respectively.
C=A+B
C = (Ax + Bx)i + (Ay + By)j
The magnitude of vector C can be calculated by adding the square of magnitude of its componets and then taking sqaure root.
Magnitude of C=
And the angle will be
Angle=arctan(Ay+By/Ax+Bx)
B strength training I think that’s the answer
Refer to the diagram shown below.
The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²
After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2
The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁
The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.
Conservation of energy requires that the loss in KE be accounted for as thermal energy.
Answer: 1/2
