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Vaselesa [24]
3 years ago
8

Identify the interaction described below. One organism benefits while the other is killed. Two species need the same resource, w

hich is limited.
Biology
2 answers:
katrin [286]3 years ago
8 0

Answer:

I think that would be amensalism or predation.

trasher [3.6K]3 years ago
3 0

Answer:

<u><em>First Set:</em></u>

Predation

Competition

<em><u>Second Set:</u></em>

Competition

Predation

Explanation:

<u><em>Predation: </em></u>One organism benefits while the other is killed.

<em><u>Competition:</u></em><u><em> </em></u>Two species need the same resource, which is limited.

<em><u>Competition:  </u></em>Two male deer will fight each other for the opportunity to mate with a female.

<em><u>Predation: </u></em>An owl catches a mouse and eats it for dinner.

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Duchenne muscular dystrophy is an X-linked recessive disease. A phenotypically normal couple wants to start a family. The woman’
Andreyy89

Answer:

\frac{1}{8}

Explanation:

From the question: Duchenne muscular dystrophy is an X-linked recessive disease.

Now for an X-linked recessive disorder to be affected by a male individual; it only requires the presence of only one copy of the recessive allele of the disease to be present BUT in a female individual. both copies of the recessive allele must be present.

Let the X-linked recessive disease(i.e Duchenne muscular dystrophy) be = (ⁿ)

However, we are told that the couples are normal and are unaffected. Therefore;

the male partner (XY) will be:   X^NY

the female partner (XY) will be: X^NX^N

Similarly, the question proceeds by telling us that: the woman's brother has the disease.

Definitely, it's possible that this unaffected woman is a carrier of the disease.

So, if she is a carrier; we have her traits to be: X^NX^n

NOW, if a cross exist between these couples; we have

X^NY     ×        X^NX^n

                     X^N                         Y

X^N                X^NX^N                  X^NY

X^n                 X^NX^n                   X^nY

So, we have offspring as follows:

X^NX^N  = normal unaffected female  

X^NY     = normal unaffected male

X^NX^n   = female carrier for the Duchenne muscular dystrophy disease

X^nY      = affected male with the Duchenne muscular dystrophy disease

So, the probability of the child to be affected with the disease = \frac{1}{4}

Also, the probability that the first child will be a male or a female = \frac{1}{2}

∴

the  probability that the couple’s first child will be affected = \frac{1}{4}*\frac{1}{2}

=\frac{1}{8}

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