Answer:
Explanation:
u = 4.6 x 10^6 m/s
Let E be the electric field
s = 3.5 cm = 0.035 m
v = 0
a = qE / m
So use third equation of motion
v^2 = u^2 - 2 a s
0 = (4.6 x 10^6)^2 - 2 x q E / m x 0.035
21.16 x 10^12 = 2 x 1.6 x 10^-19 x E / (1.67 x 10^-27 x 0.035)
E = 3865 N/C
(a) The magnitude of electric field is 3865 N/C
(b) the direction of electric field is opposite to the direction of motion of proton, i.e., towards left.
(c) Let t be the time taken
v = u + a t
0 = 4.6 x 10^6 - (1.6 x 10^-19 x 3865) t / (1.67 x 10^-27)
t = 1.24 x 10^-5 sec
(d) For electron, the direction of electric field is same the direction of electron, i.e., rightwards.
Use third equation of motion
v^2 = u^2 - 2 a s
0 = (4.6 x 10^6)^2 - 2 x q E / m x 0.035
21.16 x 10^12 = 2 x 1.6 x 10^-19 x E / (9.1 x 10^-31 x 0.035)
E = 2.1 N/C
Answer: False but read why
Heated water molecules expands ( become less dense) but they do float to the top.
The velocity of penguin as he ends where he started was 0 m/s.
<h3>What is displacement?</h3>
Displacement is the length of straight line joining the initial and final position of the body.
Given is a penguin who waddled 8 m uphill before sliding back down to its friends in 2 seconds.
We know that the velocity is the rate of change of displacement with respect to time. Mathematically -
v = dx/dt
dx = v dt
∫dx = ∫v dt
Δx = vΔt
v = Δx/Δt
Now, the displacement of the penguin will be = Δx = 8 - 8 = 0
Then, its velocity will be -
v = 0/Δt = 0
Therefore, the velocity of penguin as he ends where he started was 0 m/s.
To solve more questions on kinematics, visit the link below-
brainly.com/question/27200847
#SPJ1
The heaviest ball will have the most Potential Energy loss and Kinetic Energy gain, so your answer should be D
The answer for the following problem is mentioned below.
The option for the question is "A" approximately.
- <u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>
Explanation:
Given:
Spring constant (k) = 240 N/m
amount of the compression (x) = 0.40 m
To calculate:
Elastic potential energy (E)
We know;
<em>According to the formula;</em>
E = × k × x × x
<u>E = </u><u> × k ×(x)²</u>
where;
E represents the elastic potential energy
K represents the spring constant
x represents amount of the compression in the string
So therefore,
Substituting the values in the above formula;
E = × 240 × (0.40)²
E = × 240 × 0.16
E = × 38.4
E = 19.2 J or approximately 20 J
<u><em>Therefore the elastic potential energy of the string is 20 J.</em></u>