What is the specific heat of a substance if a mass of 10.0 kg increases in temperature from 10.0°C to 70.0°C when 2,520 J of hea
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Answer: The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is
Explanation:
The combined gas equation is,
where,
= initial pressure of gas = 0.947 atm
= final pressure of gas = 0.987 atm
= initial volume of gas = 150 ml
= final volume of gas = 144 ml
= initial temperature of gas =
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
The temperature of the gas at a pressure of 0.987 atm and volume of 144mL is