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11111nata11111 [884]
4 years ago
14

Does all matter have mass and takes up space? True False

Chemistry
1 answer:
Luden [163]4 years ago
3 0
True

the definition of matter is any substance that has mass and takes up space.
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Nitrous oxide (N2O) is used as an anesthetic (laughing gas) and in aerosol cans to produce whipped cream. It is also a potent gr
scZoUnD [109]

Answer:

five half lives

Explanation:

Half-life is the time required for a quantity to reduce to half of its initial value.

How many half lives it would take to reach 3.13% form 100% of it's initial concentration:

100% - 50% : First Half life

50% - 25%: Second Half life

25% - 12.5%: Third Half life

12.5% - 6.25%: Fourth Half life

6.25% - 3.125%: Fifth Half life

This means it would take five half lives to get to 3.125% (≈ 3.13%) of it's original concentration.

3 0
3 years ago
1) What is the mass of 6.2 mol of K2CO3?
lorasvet [3.4K]

Answer:

\boxed {\boxed {\sf 856.8648 \ grams \ of \ K_2CO_3}}

Explanation:

To convert from moles to grams, we must find the molar mass.

1. Molar Mass

First, identify the elements in the compound. K₂CO₃ It has potassium, carbon, and oxygen. Find these elements and their masses on the Periodic Table.

  • K: 39.098 g/mol
  • C: 12.011 g/mol
  • O: 15.999 g/mol

Note the subscript of 2 after K and 3 after O. We must multiply oxygen's molar mass by 2, then oxygen's by 3, and add carbon.

  • 2(39.098 g/mol) + 3(15.999 g/mol) + 12.011 g/mol= 138.204 g/mol

2. Convert Moles to Grams

Use the molar mass as a fraction.

\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}

Multiply by the given number of moles: 6.2

6.2 \ mol \ K_2CO_3 *\frac {138.204 \ g \ K_2CO_3}{1 \ mol \ K_23CO_3}

6.2  *\frac {138.204 \ g \ K_2CO_3}{1 }

6.2  * {138.204 \ g \ K_2CO_3}

856.8648 \ g \ K_2CO_3

There are <u>856.8648 grams</u> of potassium carbonate in 6.2 moles.

4 0
3 years ago
1. which volume has the most uncertainty associated wit the measurement?
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1. The option a. 10 mL has the most uncertainty associated with it, because it has only 2 significative figures, while 10.0 mL has three significant figures and 10.00 has four significant figures.

2. The volume of solution that remains is 145.675 mL - 24.2 mL = 121.475 mL rounded to one decimal  = 121.5 mL, given that the measure with the most uncerntainty has only one decimal.
 

 
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