Answer:
Part A. The half-cell B is the cathode and the half-cell A is the anode
Part B. 0.017V
Explanation:
Part A
The electrons must go from the anode to the cathode. At the anode oxidation takes place, and at the cathode a reduction, so the flow of electrons must go from the less concentrated solution to the most one (at oxidation the concentration intends to increase, and at the reduction, the concentration intends to decrease).
So, the half-cell B is the cathode and the half-cell A is the anode.
Part B
By the Nersnt equation:
E°cell = E° - (0.0592/n)*log[anode]/[cathode]
Where n is the number of electrons being changed in the reaction, in this case, n = 2 (Sn goes from S⁺²). Because the half-reactions are the same, the reduction potential of the anode is equal to the cathode, and E° = 0 V.
E°cell = 0 - (0.0592/2)*log(0.23/0.87)
E°cell = 0.017V
a. the ratio of mass to charge of an electron
Explanation:
The experiment permitted the direct measurement of the ratio of mass to charge of an electron.
- The charge to mass ratio of an electron was determine by accelerating a beam of cathode rays in magnetic and electric fields.
- No matter the gas used in the tube or the nature of the material of the electrodes, the rays were found to have constant charge to mass ratio of 1.76 x 10¹¹coulombkg⁻¹.
learn more:
Subatomic particles brainly.com/question/2757829
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Option C, mass would be same. Only the gravitational pull will be different
O: 1*2 = 2*1
<span>H 2 + 2 = 2*2 </span>
<span>answer C hope you get it right</span>
Answer:
2,500,000 litres or 2.5 megalitres of water.
Olympic size pools measure: 50 metres long, 25 metres wide, and a minimum of 2
metres deep.
(25m x 50m x 2m = 2,500m3; 1L = 0.001m3 so 2,500 x 1000 = 2,500,000L)
660,430 gallons of water.
50 meters = 164.041995 feet (a)
25 meters = 82.0209975 feet (b)
2 meters = 6.5616798 feet (c)
Volume = (a) * (b) * (c) = 88,286.66721 cubic feet Explanation:
