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k0ka [10]
3 years ago
6

Brody, The dog, is sitting at your feet like a good boy. You throw a dog toy away from you at a speed of 34 m/s (assume constant

horizontal velocity). Brody runs after the ball at a constant speed of 7 m/s. The toy is designed to make a constant high frequency tone of 950 Hz as it flies through the air.What frequency do you hear the toy make?
Physics
1 answer:
Natali [406]3 years ago
5 0

Answer: 1054.53 Hz

Explanation: this is a question under the principle of Doppler effect .

Doppler effect is a mathematical statement that gives the value of the observed frequency by an observer when there is a relative motion between the observer and the source of sound.

This is mathematically given as

fo = (v + vo)/(v - vs) × f

Where fo = observed frequency =?

v = speed of sound in air = 343 m/s

vo = velocity of observer = 0 ( since I am at rest )

vs = velocity of the source of sound ( in this case the dog toy ) = 34m/s....this value is positive because it is moving away from the observer.

f = frequency of sound produced by source = 950 Hz

By substituting the parameters, we have that

fo = (343+0)/(343-34) × 950

fo = (343/ 309) × 950

fo = 1.11 × 950 = 1054.53 Hz

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7 0
3 years ago
A 5.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical
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Answer:

17.71N/m

Explanation:

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Given

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T = 3.50s

Substitute into the formula;

T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} =  \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k =  17.71N/m

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4 0
3 years ago
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3 0
3 years ago
Read 2 more answers
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Answer:

The answer to your question is: 20

Explanation:

Atomic number is the number of proton and atom has. Each element has a specific number of protons, if the number of protons change, then this is a new element.

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