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Lana71 [14]
2 years ago
6

A 2-f and a 1-f capacitor are connected in series and a voltage is applied across the combination. the 2-f capacitor has:_______

.
Physics
2 answers:
VARVARA [1.3K]2 years ago
7 0

Half the potential difference of the the1-µF

A circuit must have a capacitance of 2 F across a 1 kV potential difference for an electrical technician. He has access to a sizable number of 1F capacitors, each of which can sustain a potential difference of no more than 400 V. Please suggest a configuration that uses the fewest capacitors possible.

The 2-mu F capacitor has the following characteristics: none of the aforementioned; half the charge of the 1-mu F capacitor; twice the charge of the 1-mu F capacitor; and half the potential difference of the 1-mu F capacitor.

Q = C V, C = Capacitance of the capacitor gives the charge stored by a capacitor with an applied voltage V. V is the applied voltage.

Learn more about capacitor brainly.com/question/21851402

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LenKa [72]2 years ago
3 0

Half the potential difference of the 1μf capacitor.

Charge: Q = CV where C is the capacitance in Farads, V is the voltage across the capacitor in Volts and Q is the charge measured in coulombs (C).

Energy stored: W = ½ QV = ½ CV×V

where W is the energy measured in Joules.

As the capacitance of a capacitor is equal to the ratio of the stored charge to the potential difference across its plates, giving: C = Q/V, thus V = Q/C as Q is constant across all series connected capacitors, therefore the individual voltage drops across each capacitor is determined by its its capacitance value.

When the capacitors are connected in the form of series combination, the capacitance in total is less than the individual capacitances of the series capacitors. If one, two or number of capacitors are connected in the series form, the overall effect is the single or equivalent capacitor which has the total sum of the spacings between the plates of the individual capacitors. The increase in the plate spacing results in the decreased capacitance, with all the other factors remaining unchanged.

learn more about series capacitance from here: brainly.com/question/28167844

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Oxygen has 6 valence electrons. how many hydrogen atoms (who have 1 valence electrons) can bond with it? remember the octet rule
astra-53 [7]

Answer:

Oxygen starts with six valance electrons and ends with six valance electrons but after bonding has parts of the densities of 8 electrons

Explanation:

Chemical bonding does not increase the valance electrons. Oxygen has 6 valence electrons. Bonding is sharing of valance electrons

The electron density of two of the valance electrons of Oxygen are shared with the Hydrogen atoms. The Hydrogen atoms is turn share part of the electron density of their single electron with Oxygen.

This means that there are parts of 8 electron densities around the Oxygen. This does not increase the number of valance electrons of Oxygen. (Note the sharing is very unfair, Oxygen gets more than its

share of the electron densities of the two electrons used for the chemical bond.

Explanation:

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3 years ago
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3 years ago
A wave has a frequency of 34 Hz and a wavelength of 2.0 m. What is the speed of the wave? Use . A. 17 m/s B. 36 m/s C. 0.059 m/s
mel-nik [20]
F= (speed)/(wavelength)

Therefore, speed = Frequency x wavelength
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8 0
4 years ago
Read 2 more answers
If you walk along a log floating on a lake why does the log move in the opposite direction?
aivan3 [116]

<em>HERE'S</em><em> </em><em>YOUR</em><em> </em><em>ANSWER</em><em>: </em>

•Since the log is stationary and you are moving beside the log, it seems to move in the opposite direction from your point of view, because from your perspective u are stationary and the log is moving. If you were to stop moving the log would also stop moving.

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5 0
3 years ago
A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How mu
irakobra [83]

Answer:

1. Concave mirror.

2. 4.17 m or 417 cm.

Explanation:

The following data were obtained from the question:

Object distance (u) = 5 m

Magnification (M) = 5

Focal length (f) =..?

1. Identification of the mirror.

To determine whether or not the mirror is concave or convex, we must first of all calculate the image distance.

This can be obtained as follow:

Object distance (u) = 5 m

Magnification (M) = 5

Image distance (v) =.?

Magnification (M) = image distance (v) /object distance (u).

M = v/u

5 = v/5

Cross multiply

v = 5 x 5

v = 25 m

Since the image distance obtained is positive, the mirror is said to be a concave mirror.

2. Determination of the focal length of the mirro.

This can be obtained as follow:

Object distance (u) = 5 m

Image distance (v) = 25 m

Focal length (f) =...?

1/f = 1/v + 1/u

1/f = 1/25 + 1/5

1/f = 0.04 + 0.2

1/f = 0.24

Cross multiply

f x 0.24 = 1

Divide both side by 0.24

f = 1/0.24

f = 4.17 m

Converting the focal length of cm, we have:

1 m = 100 cm

Therefore, 4.17 m = 4.17 x 100 = 417 cm

Therefore, the focal length of the mirror is 4.17 or 417 cm.

4 0
3 years ago
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