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STatiana [176]
3 years ago
14

Suppose an object starts out electrically neutral. Through some process, 11 electrons are removed from the object. What is the e

lectric charge of the object afterward? ANSWER
1. Unselected It has a net charge somewhere between the charge of 11 electrons and 11 protons, but we can’t tell exactly how much.
2. Unselected The stated situation isn’t possible.
3. Unselected It has the same net charge as 11 protons.
4. Unselected It has the same net charge as 11 electrons.
Physics
1 answer:
MA_775_DIABLO [31]3 years ago
5 0

Answer:

3. It has the same net charge as 11 protons.

Explanation:

An electrically neutral object contains the same number of protons and electrons. Therefore, if 11 electrons are removed from it, there will be 11 more protons compared to the number of electrons in the object. Thus, the object It has the same net charge as 11 protons.

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Objects A and B both start at rest. They both accelerate at the same rate. However, object A accelerates for 3x the time as obje
mylen [45]

Answer:

v_Object A = 3v_Object B

OR

1/3v_Object A = v_Object B

Explanation:

Let's see what variables we have in this problem.

Since the objects both start at rest, we have an initial velocity of 0 m/s.

The objects accelerate, so we will have acceleration.

Object A accelerates for 3x the time as Object B, so we have time.

The problem wants us to compare their final speeds, so we have final velocity.

Check what constant acceleration kinematic equation has these variables:

  • v = v₀ + at  

Let's create values for the unknown variables and compare the final velocities.

  • v = ?
  • v₀ = 0 m/s (objects start at rest)
  • a = 5 m/s²
  • t = 10 s

Since Object A accelerates for 3x the time as Object B, we can use t = 30 s for Object A.

Let's write the two equations:

  1. v = (0) + (5)(10)
  2. v = (0) + (5)(30)

Simplify these equations.

  1. v = 50 m/s
  2. v = 150 m/s

Let's use another set of values to compare the final velocities to see if the velocities differ by 100 m/s or Object A has 3x the final velocity of Object B.

  • v = ?
  • v₀ = 0 m/s (objects start at rest)
  • a = 3 m/s²
  • t = 7 s

Write the two equations:

  1. v = (0) + (3)(7)
  2. v = (0) + (3)(21)  

Simplify these equations.

  1. v = 21 m/s
  2. v = 63 m/s

Now we can clearly see that the final velocities are differed by 3x. Object A has 3x the final speed compared to that of Object B.

3 0
3 years ago
The motion of a car is represented as shown. The average
larisa86 [58]

Average velocity :

  • \boxed{ \boxed{ \frac{displacement }{time} }}

  • \dfrac{20}{2}

  • 10 \: ms {}^{ - 1} East

7 0
3 years ago
The spring is unstretched at the position x = 0. under the action of a force p, the cart moves from the initial position x1 = -8
hammer [34]
Missing figure and missing details can be found here:
<span>http://d2vlcm61l7u1fs.cloudfront.net/media%2Fdd5%2Fdd5b98eb-b147-41c4-b2c8-ab75a78baf37%2FphpEgdSbC....
</span>
Solution:
(a) The work done by the spring is given by
W= \frac{1}{2} k (\Delta x)^2 &#10;
where k is the elastic constant of the spring and \Delta x is the stretch between the initial and final position. Since x1=-8 in=-0.203 m and x2=5 in=0.127 m, we have
W= \frac{1}{2} \cdot 500 N/m \cdot (0.127m-(-0.203m))^2=27.25 J

(b) The work done by the weight is the product of the component of the weight parallel to the inclined plane and the displacement of the cart:
W_W = -F_{//} (x_2 -x_1)
where  the negative sign is given by the fact that F_{//} points in the opposite direction of the displacement of the cart, and where
F_{//}=m g sin 15^{\circ}=6 kg \cdot 9.81m/s^2 \cdot sin 15^{\circ}=15.2 N
therefore, the work done by the weight is
W_W=-15.2 N \cdot (0.203m-(-0.127m))=-5.02 J

8 0
3 years ago
How is force defined?​
ArbitrLikvidat [17]

Answer:

In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull.

7 0
3 years ago
Facts about Electricity and Magnetism:<br><br> Stuff Id need to know for an exam
Georgia [21]
You're in luck !  This is gonna be easy.  Listen to this:

On the exam, they're gonna put questions about all that same stuff
that they talked about IN the class all those times !  The exact same
material.  And if they didn't talk about it in class, then it won't be on
the exam !    How cool is that ? !

All that stuff you copied from the board, all those notes you wrote in
your notebook so you'd remember it, all those handouts they gave out
in class, all that homework you did ... THAT's what they'll put on the exam !

It's gonna be all stuff that you seen and heard and studied before.
No surprises.  It'll be a breeze, and you're totally gonna do fine. 
4 0
3 years ago
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