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8_murik_8 [283]
3 years ago
14

A car is on a circular off ramp of an interstate and is traveling at exactly 25 mph around the curve. Does the car have velocity

? Yes No Does the car have acceleration? Yes No Is the car decelerating? Yes No
Physics
1 answer:
netineya [11]3 years ago
6 0

Answer:

The car has velocity and acceleration but is not decelerating

Explanation:

Since the car is traveling at 25 mph around the curve, it has a tangential velocity. This tangential velocity is constantly changing in direction (so the car could adapt to the curve and not moving forward in a straight line), there should be a centripetal acceleration in play here. This acceleration does not slow down the car so it's not decelerating.

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Q/C An undersea earthquake or a landslide can produce an ocean wave of short duration carrying great energy, called a tsunami. W
iragen [17]

The amplitude A_{2} is 8.307 m

When describing the peak value of a quantity, such as the level of sound waves or the power and voltage in electrical and electronic systems, the term amplitude is employed. A louder sound has a bigger amplitude, and a softer sound has a smaller amplitude.

As we previously discussed in the concept session, the square root of the water's speed is inversely related to the amplitude of its waves.

A\alpha\frac{1}{\sqrt{v} }

Solve for first case:

A_{1}=\frac{1}{\sqrt{v_{1} } }

Solve for second case:

A_{2}=\frac{1}{\sqrt{v_{2} } }

So, the two equations is equal

A^{2} _{1}  v_{1} = A^{2} _{2} v_{2}

        =A^{2} _{2} \sqrt{g d_{2} }

Rearrange and solve for the amplitude A_{2} :

A_{2} =\sqrt{\frac{A^{2}_{1} v_{1} }{v_{2} } }

    =\sqrt{\frac{A^{2}_{1} v_{1}  }{\sqrt{g d_{2} } } }

    =\sqrt{\frac{(1.8m)^{2} X200 m/s }{\sqrt{9.8m/s^{2}X9 m } } }

    = 8.307 m

So, The amplitude A_{2} is 8.307 m.

Learn more about amplitude here:

brainly.com/question/3613222

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