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8_murik_8 [283]
2 years ago
14

A car is on a circular off ramp of an interstate and is traveling at exactly 25 mph around the curve. Does the car have velocity

? Yes No Does the car have acceleration? Yes No Is the car decelerating? Yes No
Physics
1 answer:
netineya [11]2 years ago
6 0

Answer:

The car has velocity and acceleration but is not decelerating

Explanation:

Since the car is traveling at 25 mph around the curve, it has a tangential velocity. This tangential velocity is constantly changing in direction (so the car could adapt to the curve and not moving forward in a straight line), there should be a centripetal acceleration in play here. This acceleration does not slow down the car so it's not decelerating.

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A force of 6N is exerted on a cart that is carrying a rock and produces an acceleration of 2 m/s2. If the cart has a mass of 1 k
vaieri [72.5K]
If you use the equation F=ma and re-arrange it to get m = F/a, you'll get the total mass. Then you have to subtract the mass of the cart from the total mass to get the mass of the rock. 

Thus, m = 6N over 2m/s^2. The total mass will then be 3kg. Subtracting 1kg from the total mass will then yield you 2kg, which is the mass of the rock. Hope this helps.
6 0
2 years ago
Urippe Went to start his lawnmower and was having trouble. At the same moment, Uwi was starting her identical lawnmower in the y
Ivan

Answer:

As each mower presumably needs the same torque to start, and torque is a product of force and moment arm, the longer moment arm of 10.42 cm on Uwi's mower means lower force is required when compared to Urippe's shorter moment arm of 1.35 cm

350 rev/min = 350(2π) / 60 = 36.652 rad/s

36.652 rad/s / 0.294 s = 124.66... <u>125 rad/s²</u>

a = αR = 125(0.1042) = 12.990... <u>13 m/s²</u>

a =  αR = 125(0.0135) = 1.68299... <u>1.7 m/s²</u>

I am GUESSING that we are supposed to model these mowers as a uniform disk

  τ = Iα

FR = (½mr²)α

  F = mr²α/2R

Urippe's pull  = (3.56)(0.2041²)(124.66) / (2(0.0135)) = 702.008... <u>702 N</u>

Usi's pull =        (3.56)(0.2041²)(124.66) / (2(0.1042)) = 90.9511...<u>91.0 N</u>

L = Iω = (½(3.56)(0.2041²))36.652 = 2.71771...<u>2.72 kg•m²/s  down</u>

using the right hand rule

8 0
2 years ago
A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surfac
zhuklara [117]

Answer:

W=76.55 miles.metric tons

Explanation:

Given that

Weight on the earth = 12 tons

So weight on the moon =12/6 = 2 tons

 ( because at moon g will become g/6)

As we know that

F=\dfrac{K}{x^2}

Here x= 1100 miles

F 2 tons

2=\dfrac{K}{1100^2}

So

K=2.4\times 10^6

We know that

Work = F. dx

W=\int_{x_1}^{x_2}F.dx

W=\int_{1100}^{1140}\dfrac{2.4\times 10^6}{x^2}.dx

W=-2.4\times 10^6\left[\dfrac{1}{x}\right]_{1100}^{1140}

W=-2.4\times 10^6\left[\dfrac{1}{1140}-\dfrac{1}{1100}\right]

W=76.55 miles.metric tons

6 0
2 years ago
What is energy and object has due to its motion
jolli1 [7]
The energy stored in motion is called kinetic energy.
3 0
3 years ago
Two speakers, one directly behind the other, are each generating a 280-Hz sound wave. What is the smallest separation distance b
Annette [7]

Answer:

1.21m

Explanation:

If two speakers are generating a frequency of 280Hz, the smallest separation distance between the speakers that will produce destructive interference at a listener standing in front of them is also known as the wavelength of the sound wave generated.

Using the expression;

Velocity v = frequency f × wavelength ¶

Given frequency = 280Hz, speed of sound v = 338m/s

Substituting this data's in the expression given to get the wavelength will give;

¶ = v/f

¶ = 338/280

¶ = 1.21m

The smallest separation between the speakers that will produce the interference is 1.21m

4 0
3 years ago
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