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SpyIntel [72]
3 years ago
5

if a girl is running along a straight road with uniform velocity 1.5 metre per second find the acceleration​

Physics
1 answer:
PilotLPTM [1.2K]3 years ago
4 0

Answer:

Acceleration is 0.

Explanation:

Since the girl is running with a uniform velocity, meaning she is moving at a constant rate, she is not accelerating. Acceleration only occurs when the speed of an object increases, decreases, or if there is a change in direction.

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You are on an airplane traveling with a constant velocity at an altitude of 20,000m. What is the acceleration of gravity at that
-BARSIC- [3]
The correct answer would be A.The acceleration of gravity is <span>9.81 m/s^2. This is calculated by using the equation:

a = GM/r</span>²

where G is the gravitational constant 6.6726 x 10-11N-m2/kg2, M is the mass of the planet (<span>5.9736E+24 kg) and r is the radius of the planet.
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3 0
3 years ago
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At launch a rocket ship weighs 4.5 million pounds. When it is launched from rest, it takes 8.00 s to reach 161 km/h; at the end
SpyIntel [72]

Answer:

5.590278\ m/s^2

7.74038461538\ m/s^2

178.888896 m

12790.56 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{161}{3.6}-0}{8}\\\Rightarrow a=5.590278\ m/s^2

The acceleration is 5.590278\ m/s^2

v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{1610}{3.6}-\dfrac{161}{3.6}}{60-8}\\\Rightarrow a=7.74038461538\ m/s^2

The acceleration is 7.74038461538\ m/s^2

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 5.590278\times 8^2\\\Rightarrow s=178.888896\ m

Distance traveled in the first 8 seconds is 178.888896 m

s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=\dfrac{161}{3.6}\times 52+\dfrac{1}{2}\times 7.74038461538\times 52^2\\\Rightarrow s=12790.56\ m

Distance traveled during 8-60 second interval is 12790.56 m

6 0
3 years ago
Part F What are some potential applications of a material that make things invisible?​
Sveta_85 [38]

Answer:

Its ahhshshgd

Explanation:

Very welcome mate.

8 0
3 years ago
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Given the equation p2 = a3, what is the orbital period, in days, for the planet venus? (venus is located 0.72 au from the sun?)
melisa1 [442]

The correct answer is 223 days.

The relationship between the duration of revolution and the separation between the sun is shown by Kepler's third law. Using the notions of circular motion and the gravitational and centripetal forces, we may obtain this equation.

According to Kepler's third rule, the semi-major axis of an orbit is linked to the orbital period of a planet around the sun as follows:

p² = a³

where an is the semi-major axis/distance to the star and p is the orbital period in years.

It is said that a = 0.72 AU for Venus.

P= √(0.72 AU)^3 = 0.61 years.

365 days in a year = 222.9 ≈ 223 days.

To learn more about Kepler's third rule refer the link:
brainly.com/question/1608361

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5 0
1 year ago
PLEASE HLEP I WILL GIVE BRAINLIEST TO CORRECT ANSWER!!!!!!
Hoochie [10]

Answer:

75 km/h

Explanation:

Speed = Distance divided by Time.

The train went a distance of 300 km in 4 hours. Therefore, the speed of the train is: 300 divided by 4 = 75 km/h

8 0
3 years ago
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