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Verizon [17]
3 years ago
13

Which would be a common-sense practice in a lab environment?

Physics
1 answer:
algol133 years ago
6 0
Using safe research practices would be a very good common-sense practice in a lab environment.
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Please help me!! &lt;3 <br> Am I right??
aliina [53]
Yes you are right, Good Luck!
7 0
4 years ago
How does the force due to gravity on Mars compare to the force due to gravity on Earth? , and Using Newton's Second Law, explain
zubka84 [21]
As accurately described by Einstein's theory of relativity, gravity is not necessarily a force, but a consequence of the curvature of space time that is caused by the uneven distribution of mass. But this could also be approximated by Newton's Law of Universal Motion. Gravity is a force acting upon two objects with masses at a certain amount of distance. So, the greater the mass, and the closer the objects are, the greater is the force of gravity. So, if you compare the gravity on Mars compared to Earth at a given distance, compare their masses. The mass of Earth is 5.972 × 10^24 kg while that of Mars is <span>6.39 × 10^23 kg. So, the gravity on Earth is much greater because Earth is heavier.

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4 0
3 years ago
A helium-neon laser beam has a wavelength in air of 633 nm. It takes 1.38 ns for the light to travel through 32.0 cm of an unkno
Vera_Pavlovna [14]

Answer:

Wavelength = 489.52 nm

Explanation:

Given that the wavelength of the light = 633 nm

The time taken by the light in unknown liquid = 1.38 ns

Also,

1 ns = 10⁻⁹ s

So, t = 1.38 × 10⁻⁹ s

Also,

Distance = 32.0 cm = 0.32 m ( 1 cm = 0.01 m)

<u>So, speed of the light in the liquid = Distance / Time = 0.32 / 1.38 × 10⁻⁹ m/s = 2.32 × 10⁸  m/s</u>

Frequency of the light does not change when light travels from one medium to another. So,

\frac {V_{air}}{\lambda_{air}}=\frac {V_{liquid}}{\lambda_{liquid}}

{V_{air}}=3\times 10^8\ m/s

{\lambda_{air}}=633\ nm

{V_{liquid}}=2.32\times 10^8\ m/s

{\lambda_{liquid}}=?\ nm

So,

\frac {3\times 10^8\ m/s}{633\ nm}=\frac {2.32\times 10^8\ m/s}{\lambda_{liquid}}

<u>Wavelength = 489.52 nm</u>

4 0
3 years ago
A car is going through a dip in the road whose curvature approximates a circle of radius 200 m. At what velocity will the occupa
boyakko [2]

Answer:

Explanation:

The solution along with the diagram can be found in the attachment. Feel free to raise doubts.

4 0
3 years ago
Which of the following numbers is equal to an object's acceleration?
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<span>C. the slope of that objects velocity-time graph

Hope it helps!
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5 0
3 years ago
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