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Verizon [17]
3 years ago
13

Which would be a common-sense practice in a lab environment?

Physics
1 answer:
algol133 years ago
6 0
Using safe research practices would be a very good common-sense practice in a lab environment.
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An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos
disa [49]

The sign associated with the average velocity of the object is negative.

<h3>Average velocity of the object</h3>

The average velocity of the object is calculated as follows;

Average velocity = (v1 + v2)/2

v1 = -20/30 = -0.667 m/s

v2 = 20/50 = 0.4 m/s

Average velocity = (-0.667 + 0.4)/2

Average velocity  = -0.134 m/s

Thus, the sign associated with the average velocity of the object is negative.

Learn more about average velocity here: brainly.com/question/6504879

#SPJ1

7 0
2 years ago
An electron accelerated from rest through a voltage of 780 v enters a region of constant magnetic field. part a part complete if
maxonik [38]
The electron is accelerated through a potential difference of \Delta V=780 V, so the kinetic energy gained by the electron is equal to its variation of electrical potential energy:
\frac{1}{2}mv^2 =  e \Delta V
where
m is the electron mass
v is the final speed of the electron
e is the electron charge
\Delta V is the potential difference

Re-arranging this equation, we can find the speed of the electron before entering the magnetic field:
v= \sqrt{ \frac{2 e \Delta V}{m} } = \sqrt{ \frac{2(1.6 \cdot 10^{-19}C)(780 V)}{9.1 \cdot 10^{-31} kg} }=1.66 \cdot 10^7 m/s


Now the electron enters the magnetic field. The Lorentz force provides the centripetal force that keeps the electron in circular orbit:
evB=m \frac{v^2}{r}
where B is the intensity of the magnetic field and r is the orbital radius. Since the radius is r=25 cm=0.25 m, we can re-arrange this equation to find B:
B= \frac{mv}{er}= \frac{(9.1 \cdot 10^{-31}kg)(1.66 \cdot 10^7 m/s)}{(1.6 \cdot 10^{-19}C)(0.25 m)} =3.8 \cdot 10^{-4} T
3 0
4 years ago
Particles q1, 92, and q3 are in a straight line.
Kisachek [45]

The answer to the question is 1.125  Newton

Formula for electrostatic force is F = ( K q1 q2 )/ r²

where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.

Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.

Electrostatic force between q1 and q3

r will be 0.500 + 0.500 = 1 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²

F₁₃ = 2.25  × 10⁻¹ N

Electrostatic force between q2 and q3

r will be 0.500 m

F = ( K q1 q3 )/ r²

F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²

F = (225 × 10⁻³) / (25 × 10⁻²)

F₂₃ = 9 × 10⁻¹ N

Total force on q3 will be F₁₃ + F₂₃

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 2.25  × 10⁻¹ ) + (9 × 10⁻¹ ) N

Total force on q3 =  ( 11.25  × 10⁻¹ ) N

Total force on q3 =  1.125  N

Thus after solving we got the net force on q3 as 1.125  Newton

Learn more about Electrostatic Force here:

brainly.com/question/23121845

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7 0
2 years ago
Starting from rest on a level road a girl can reach a speed of 5 m/s in 10s on her bicycle. Find average speed and distance trav
Mice21 [21]

Answer:

Average speed = 2.5 mph

Distance = 22.352 meters

Explanation:

Calculate speed, distance or time using the formula d = st, distance equals speed times time.

Calculate speed, distance or time using the formula d = st, distance equals speed times time.

You can use this formula for any question like this

8 0
2 years ago
Which of the following forces can both attract and repel some objects without touching them?
nasty-shy [4]

Answer:

A. Magnetism

B. Spring

( I'm not so sure about the second answer, but I'm certain about the first one)

Explanation:

5 0
4 years ago
Read 2 more answers
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