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Alenkinab [10]
3 years ago
14

How much tension must a rope withstand if it is used to accelerate a 960 kg car horizontally along a frictionless track at 1.20

m/s²?
Physics
2 answers:
raketka [301]3 years ago
5 0

Answer:

<em>The tension of the rope is 1152 N</em>

Explanation:

<u>Force</u>

Newton's second law states that the acceleration of an object is directly proportional to the net force and inversely related to its mass.

The law can be written as:

F = m.a

The rope must apply a force F to accelerate the car of m=960 Kg at a=1.2~ m/s^2. Given the track is frictionless, all the force applied produces acceleration, thus:

F = 960~Kg\cdot 1.2~ m/s^2

F = 1152 N

The tension of the rope is 1152 N

EleoNora [17]3 years ago
4 0
T=ma
T=960*1.2
T=1152 N
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Answer:

The answer to your question is: C. -9.81 m/s²

Explanation:

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When you take your 1900-kg car out for a spin, you go around a corner of radius 55 m with a speed of 15 m/s. The coefficient of
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Answer:

7772.72N

Explanation:

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Now which direction is the static friction, assume that it is pointing inward so

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Electromagnetic waves can travel through a vacuum, that is an empty space, whereas mechanical waves cannot. They need a medium to travel such as water or air. Ripples in a pond are an example of mechanical waves whereas electromagnetic waves include light and radio signals, which can travel through the vacuum of space.

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                                                                            Have a wonderful day!

                                                                                                ~Lillith of brainly~

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2 years ago
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