How much tension must a rope withstand if it is used to accelerate a 960 kg car horizontally along a frictionless track at 1.20
2 answers:
Answer:
<em>The tension of the rope is 1152 N</em>
Explanation:
<u>Force</u>
Newton's second law states that the acceleration of an object is directly proportional to the net force and inversely related to its mass.
The law can be written as:
F = m.a
The rope must apply a force F to accelerate the car of m=960 Kg at . Given the track is frictionless, all the force applied produces acceleration, thus:
F = 1152 N
The tension of the rope is 1152 N
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Answer:
Ratio of length will be
Explanation:
We have given time period of the pendulum when length is is
And when length is time period
We know that time period is given by
So ----eqn 1
And -------eqn 2
Dividing eqn 2 by eqn 1
Squaring both side
According to Ideal gasTo solve this problem, the fastest relationship allows us to observe the proportionality between the two variables would be the one expressed in the ideal gas equation, which is
Here
P = Pressure
V = Volume
N = Number of moles
R = Gas constant
T = Temperature
We can see that the pressure is proportional to the temperature, then
This relationship can be extrapolated to all the scenarios in which these two variables are related. As the pressure increases the temperature increases. The same goes for the pressure in the atmosphere, for which an increase in this will generate an increase in temperature. This variable can be observed in areas of different altitude. At higher altitude lower atmospheric pressure and lower temperature.