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Alenkinab [10]
3 years ago
14

How much tension must a rope withstand if it is used to accelerate a 960 kg car horizontally along a frictionless track at 1.20

m/s²?
Physics
2 answers:
raketka [301]3 years ago
5 0

Answer:

<em>The tension of the rope is 1152 N</em>

Explanation:

<u>Force</u>

Newton's second law states that the acceleration of an object is directly proportional to the net force and inversely related to its mass.

The law can be written as:

F = m.a

The rope must apply a force F to accelerate the car of m=960 Kg at a=1.2~ m/s^2. Given the track is frictionless, all the force applied produces acceleration, thus:

F = 960~Kg\cdot 1.2~ m/s^2

F = 1152 N

The tension of the rope is 1152 N

EleoNora [17]3 years ago
4 0
T=ma
T=960*1.2
T=1152 N
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