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Fofino [41]
3 years ago
9

Many meteorites appear to have formed very early in the solar system's history. How do these meteorites support our theory about

how the terrestrial planets formed
Physics
1 answer:
tigry1 [53]3 years ago
6 0

Answer:

The appearance and composition of meteorites is what we would expect if metal and rock condensed and increased as our theory suggests.

Explanation:

The planets and most of their satellites were formed by accretion of matter that accumulated around the largest pieces of the proto-nebula. After a chaotic succession of collisions, mergers and reconstruction processes, they acquired a size similar to the current one and moved until they were in the positions we know.

The area closest to the Sun was too warm to retain light materials. That is why the inner planets are small and rocky, while the outer ones are large and gaseous. The evolution of the Solar System has not stopped, but, after the initial chaos, most of the materials are now part of bodies located in more or less stable orbits.

Any theory that attempts to explain the formation of the Solar System should take into account that the Sun rotates slowly and only has 1 percent of the angular momentum, but it has 99.9% of its mass, while the planets have 99% of the angular momentum and only 0.1% of the mass. One of the explanations argues that, at first, the Sun was much colder; The density of its materials was slowing its rotation, while warming, until a certain balance was achieved.

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2 years ago
Power Rating of a Resistor. The power rating of a resistor is the maximum power the resistor can safely dissipate without too gr
IgorLugansk [536]

(a) 273.9 V

The power rating of the resistor is given by

P=\frac{V^2}{R}

where

P is the power rating

V is the potential difference across the resistor

R is the resistance

If the maximum power rating is P=5.0 W, and the resistance of the resistor is R=15 k\Omega = 15000 \Omega, then we can find the maximum potential difference across the resistor by re-arranging the previous equation for V:

V=\sqrt{PR}=\sqrt{(5.0 W)(15000 \Omega)}=273.9 V

(b) 1.6 W

In this case, we have:

R=9.0 k\Omega = 9000 \Omega is the resistance of the resistor

V=120 V is the potential difference across the resistor

So we can find the power rating by using the same formula of part (a):

P=\frac{V^2}{R}=\frac{(120 V)^2}{9000 \Omega}=1.6 W

(c) Maximum voltage: 14.1 V; Rate of heat: 2.00 W and 3.00 W

Here we have two resistors of

R_1 = 100 \Omega\\R_2 = 150 \Omega

and each resistor has a power rating of

P = 2.00 W

So the greatest potential difference allowed in the first resistor is

V=\sqrt{PR_1}=\sqrt{(2.00 W)(100 \Omega)}=14.1 V

While the greatest potential difference allowed in the second resistor is

V=\sqrt{PR_2}=\sqrt{(2.00 W)(150 \Omega)}=17.3 V

So the greatest potential difference allowed not to overheat either of the resistor is 14.1 V.

In this condition, the power dissipated on the first resistor is 2.00 W, while the power dissipated on the second resistor is

P_2 = \frac{V^2}{R_2}=\frac{(14.1 V)^2}{150 \Omega}=1.33 W

And this corresponds to the rate of heat generated in the first resistor (2.00 W) and in the second resistor (1.33 W).

4 0
2 years ago
What are beats? A. periodic fluctuations in the velocity of sound waves B. periodic fluctuations in the wavelength of sound wave
777dan777 [17]

The answer is

C. periodic fluctuations in the intensity if sound waves.

3 0
3 years ago
Read 2 more answers
Glass is transparent to visibile light under normal conditions; however, at extremely high intensities, glass will absorb most o
8_murik_8 [283]

Answer:

3 photons

Explanation:

The energy of a photon E can be calculated using this formula:

E=\frac{hc}{\lambda}

Where h corresponds to Plank constant (6.626070x10^-34Js), c is the speed of light in the vacuum (299792458m/s) and \lambda is the wavelength of the photon(in this case 800nm).

E=\frac{hc}{\lambda}=\frac{(6.626070\times10^{-34})(299792458)}{800\times10^{-9}}=\frac{1.986445812\times10^-25}{800}=2.483057265\times10^{-19}J

Tranform the units

1eV=1.602176634\times10^{-19}J\\2.483057265\times10^{-19}J(\frac{1eV}{1.602176634\times10^{-19}J})=1.549802445eV

The band Gap is 4eV, divide the band gap between the energy of the photon:

\frac{4ev}{1.549802445eV}=2.508974118

Rounding to the next integrer: 3.

Three photons are the minimum to equal or exceed the band gap.

4 0
3 years ago
Two resistors, of R1 = 3.93 Ω and R2 = 5.59 Ω, are connected in series to a battery with an EMF of 24.0 V and negligible interna
son4ous [18]

Answer:

2.521 (A); 14.0924 (V)

Explanation:

more info in the attachment, the answers are marked with red colour.

4 0
2 years ago
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