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3 years ago

A speed-time graph is shown below:

Physics

1 answer:

Juliette [100K]3 years ago

4 0

Answer:

It traveled 4 centimeters.

Explanation:

In a speed versus time graph, the distance travelled is given by the area under the graph.

In this graph we have the following:

- The speed of the object is v = 1 cm/s between time t = 0 s and t = 4 s

- The speed of the object is v = 0 cm/s between time t = 4 s and t = 8 s

Since the speed in the second part is zero, the distance travelled in the second part is zero. So, the only distance travelled by the object is the distance travelled during the first part, which is equal to the area of the first rectangle:

$d=v\Delta t=(1)(4-0)=4 cm$

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Another droplet of the same mass falls 8.4 cm from rest in 0.250 s, again moving through a vacuum. Find the charge carried by th

Andrej [43]

Answer:

The charge carried by the droplet is $1.330\times10^{-19}\ C$

Explanation:

Given that,

Distance =8.4 cm

Time = 0.250 s

Suppose tiny droplets of oil acquire a small negative charge while dropping through a vacuum in an experiment. An electric field of magnitude $5.92\times10^4\ N/C$ points straight down and if the mass of the droplet is $2.93\times10^{-15} kg$

We need to calculate the acceleration

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

Put the value into the formula

$8.4\times10^{-2}=0+\dfrac{1}{2}\times a\times(0.250)^2$

$a=\dfrac{8.4\times10^{-2}\times2}{(0.250)^2}$

$a=2.688\ m/s^2$

We need to calculate the charge carried by the droplet

Using formula of electric filed

$E=\dfrac{F}{q}$

$q=\dfrac{ma}{E}$

Put the value into the formula

$q=\dfrac{2.93\times10^{-15}\times2.688}{5.92\times10^4}$

$q=1.330\times10^{-19}\ C$

Hence, The charge carried by the droplet is $1.330\times10^{-19}\ C$

8 0

3 years ago

A circular loop of radius 11.9 cm is placed in a uniform magnetic field. (a) If the field is directed perpendicular to the plane

djverab [1.8K]

Answer:

(a). The strength of the magnetic field is 0.1933 T.

(b). The magnetic flux through the loop is zero.

Explanation:

Given that,

Radius = 11.9 cm

Magnetic flux $\phi=8.60\times10^{-3}\ T m^2$

(a). We need to calculate the strength of the magnetic field

Using formula of magnetic flux

$\phi=BA\cos\theta$

$\phi=BA\cos0$

$\phi=BA$

$B=\dfrac{\phi}{A}$

$B=\dfrac{\phi}{\pi r^2}$

Put the value into the formula

$B=\dfrac{8.60\times10^{-3}}{\pi\times(11.9\times10^{-2})^2}$

$B=0.1933\ T$

(b). If the magnetic field is directed parallel to the plane of the loop,

We need to calculate the magnetic flux through the loop

Using formula of flux

$\phi=BA\cos\theta$

Here, $\theta=90^{\circ}$

$\phi=BA\cos90$

$\phi=0$

Hence, (a). The strength of the magnetic field is 0.1933 T.

(b). The magnetic flux through the loop is zero.

3 0

3 years ago

Read 2 more answers

How do you verify scientific hypothesis?

sergeinik [125]

They verify scientific hypothesis by doing experiments do prove what their theory was.

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4 years ago

A mailman performed 296 J of work lifting a box of 1.6 m. How much force did the mailman use?

Rus_ich [418]

185 newtons because (W=Fd so W/d=F)296/1.6=185

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3 years ago

An apple falls from a tree and 2.5 seconds later hits the ground. How fast is the apple falling when it hits the ground? Neglect

denis-greek [22]

Answer:

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3 years ago