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Viktor [21]
3 years ago
7

NEED HELP NOW. I need help finding the x-intercepts.

Mathematics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

To find the x-intercepts we can write:

0 = -1/2(x + 3)² + 4

0 = -1/2(x² + 6x + 9) + 4

0 = -1/2x² - 3x - 9/2 + 4

0 = -1/2x² - 3x - 1/2

0 = x² + 6x + 1

x = -3 ± 2√2 (use quadratic formula)

As a decimal this can be written as x = -5.83, x = -0.17.

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there are 680 students and Cassie's High School 40% of the students are taking Spanish how many students are taking Spanish​
snow_lady [41]
272

680 x 0.40 = 272
8 0
3 years ago
Question help a lottery game has balls numbered 0 through 1313. what is the probability of selecting an even numbered ball or a
Licemer1 [7]
So i'm assuming 33^a is saying any number that is a square of 33 inside of 1,313 so first, to find how many even numbers divide 1,313 by two to get 656.5 so if I am not mistaken 656 numbers in 1,313 will be even. Now find all squares of 33 that don't pass 1,313 which is 33 itself and 1,089 because 33^3 is 35,937 so add 2 to 656 to get 668. so the probability is 658/1,313 i believe.
7 0
3 years ago
Harpreet, Sukhpreet and Komalpreet are three sisters. Sukhpreet is x years old. Harpreet is 3 years older than Sukhpreet. Komalp
Ira Lisetskai [31]

Answer:

12

Step-by-step explanation:

Givens

Harpreet        = x + 3

Sukhpreet     = x

Komalpreet   = 2*(x + 3)

Average Age = 15

Equation

[(x + 3) + x + 2*(x + 3) ] / 3 = 15                  Multiply both sides by 3

Solution

3 [(x + 3) + x + 2*(x + 3) ] / 3 = 15 * 3         Combine

 [(x + 3) + x + 2*(x + 3) ]       =   45             Remove the brackets

x + 3 + x + 2x + 6                 =   45             Combine like terms

4x + 9 = 45                                                 Subtract 9 from both sides

4x + 9 - 9 = 45 - 9                                       Combine

4x = 36                                                         Divide by 4

4x/4 = 36/4

x = 9

Answer

Harpreet is  x+ 3 = 9 + 3 = 12

3 0
2 years ago
Composition of functions Find g (f(x)) for the following problems
beks73 [17]

1.

f(x)=-3x\qquad g(x)=5x-6\\\\g(f(x))=5(-3x)-6=\boxed{-15x-6}

2.

f(x)=x-6\qquad g(x)=x^2+6x-2\\\\g(f(x))=(x-6)^2+6(x-6)-2=x^2-12x+36+6x-36-2=\\\\=\boxed{x^2-6x-2}

3.

f(x)=4x+3\qquad g(x)=2x^2-x+1\\\\g(f(x))=2(4x+3)^2-(4x+3)+1=2(16x^2+24x+9)-4x-3+1=\\\\=32x^2+48x+18-4x-3+1=\boxed{32x^2+44x+16}

4.

f(x)=2x^2\qquad g(x)=8x^2+3x\\\\g(f(x))=8(2x^2)^2+3(2x^2)=8\cdot4x^4+6x^2=\boxed{32x^4+6x^2}

7 0
3 years ago
Find the surface area of the cone to the nearest tenth.
vfiekz [6]
Surface area = base area + side area

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7 0
3 years ago
Read 2 more answers
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