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tigry1 [53]
3 years ago
9

A day-care center has 2 baskets of dolls. One basket has 8 dolls, and the other basket has an unknown number of dolls in it. Wha

t expression can you use to represent this situation?
Mathematics
1 answer:
xenn [34]3 years ago
3 0

Answer:

d+8

Step-by-step explanation:

Let d represent number of dolls in 2nd basket.

We have been given that a day-care center has 2 baskets of dolls. One basket has 8 dolls, and the other basket has an unknown number of dolls in it. We are asked to represent this situation in an expression.

The number in both baskets would be equal to dolls in 1st basket plus dolls in 2nd basket.

We can represent this information in an expression as:

d+8

Therefore, our required expression would be d+8, where d represents number of dolls in 2nd basket.

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it takes 47 minutes for 7 people to paint 7 walls. how many minutes does it take 20 people to paint 20 walls?
4vir4ik [10]

Answer:

7 people, 7 walls, 48 minutes

 

Each person paints 1 wall in 48 minutes

 

20 persons, 20 walls


Each person can paint 1 wall in 48 minutes so it will  take 48 minutes.



6 0
3 years ago
Find the smallest positive integer value of n for which 225n is a multiple of 540.​
krek1111 [17]

Answer:

mark me as brainliest and follow and like my answer

Step-by-step explanation:

225n=540

n=2.4

5 0
3 years ago
Solve.<br><br> Round to the nearest hundredth.<br><br> 29.3 = 1.7y
Elena-2011 [213]

Steps to Solve:

29.3 = 1.7y

29.3/1.7 = 1.7y/1.7

y = 17.2352941176

In this case, we round up the hundredths place because the number in the thousandths place is 5 or higher.

y = 17.24

Hope this helps!! :)

7 0
4 years ago
Read 2 more answers
X 1/2 rational exponent
Lesechka [4]

Answer:

Step-by-step explanation:

Ok

7 0
3 years ago
Find the fifth roots of 243(cos 240° + i sin 240°).
Mazyrski [523]

Answer:

See below.

Step-by-step explanation:

Fifth root of 243 = 3,

Suppose r( cos Ф + i sinФ) is the fifth root of 243(cos 240 + i sin 240),

then r^5( cos  Ф  + i sin  Ф )^5 = 243(cos 240 + i sin 240).

Equating equal parts and using de Moivre's theorem:

r^5 =243  and  cos  5Ф  + i sin  5Ф = cos 240 + i sin 240

r = 3 and  5Ф = 240 +360p so Ф =  48 + 72p

So Ф = 48, 120, 192, 264, 336  for   48 ≤ Ф < 360

So there are 5 distinct solutions given by:

3(cos 48 + i sin 48),

3(cos 120 + i sin 120),

3(cos 192 + i sin 192),

3(cos 264 + i sin 264),

3(cos 336 + i sin 336).. (Answer).

7 0
3 years ago
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