PLEASE HELP ME on this question.

An object of mass, m1 with a velocity, v1 collides with another object at rest (v2 = 0) with a mass, m2. After the collision, m1

goblinko [34]

Answer:

$v"_{1} = v_{1} tan$ Θ

$v^{"} _{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

Θ = $tan^{-1}(\frac{v^{"} _{1} }{v_{1} } )$

Explanation:

Applying the law of conservation of momentum, we have:

Δ $p_{x = 0}$

$p_{x} = p"_{x}$

$m_{1}v_{1} = m_{2}v"_{2} cos$ Θ (Equation 1)

Δ $p_{y} = 0$

$p_{y} = p"_{y}$

$0 = m_{1} v"_{1} - m_{2} v"_{2} sin$ Θ (Equation 2)

From Equation 1:

$v"_{2} = \frac{m_{1}v_{1}}{m_{2}cos}$ Θ

From Equation 2:

$m_{2} v"_{2}$ sinΘ = $m_{1} v_{1}$

$v"_{1} = \frac{m_{2} v"_{2}sinΘ}{m_{1} }$

Replacing Equation 3 in Equation 4:

$v"_{1}=\frac{m_{2}\frac{m_{1}v_{1}}{m_{2}cosΘ}sinΘ}{m_{1}}$

$v"_{1}=v_{1}\frac{sinΘ}{cosΘ}$

$v"_{1}=v_{1}tan$ Θ (Equation 5)

And we found Θ from the Equation 5:

tanΘ= $\frac{v"_{1}}{v_{1}}$

Θ= $tan^{-1}(\frac{v"_{1}}{v_{1}})$

7 0

3 years ago

A ball is dropped from the top of a cliff. By the time it reaches the ground, all of its gravitational potential energy has been

Katena32 [7]

Answer:

20 m

Explanation:

Initial potential energy = final kinetic energy

mgh = 1/2 mv²

gh = 1/2 v²

h = v² / (2g)

Given v = 20 m/s and g = 10 m/s²:

h = (20 m/s)² / (2 × 10 m/s²)

h = 20 m

4 0

3 years ago

Line spectra from all regions of the electromagnetic spectrum, including the Paschen series of infrared lines for hydrogen, are

zlopas [31]

Answer:

λ = 3.4 × 10^18m

Explanation:using Rydberg equation:

1/λ = RH •Z^2[ (1/n1) - (1/n2) ]

RH = Rydberg constant = 2.18x 10^-18j)

n1 and n2 = energy levels (n2 >n1)

Z = atomic number = 4

Substitute

1/λ = 2.18x 10^-18• [ (1/3) - (1/5) }

λ = 3.4 × 10^18m

4 0

3 years ago

a bear has a mass of 500kg and 100,000 J of mechanical kinetic energy. what is the speed of the bear?

3241004551 [841]

Answer: v = 20 m/s

Explanation: Solution:

Use the formula of Kinetic Energy and derive for v:

KE = 1/2 mv²

To find v:

v = √ 2 KE / m

= √ 2 ( 100000 J ) / 500 kg

= √ 400 m/s

= 20 m/s

7 0

4 years ago

A rod made from insulating material carries a net charge, while a copper sphere is neutral. The rod and the sphere do not touch.

navik [9.2K]

<span>As the charged insulating rod approaches the sphere (not in contact), free electrons in the sphere move. If the rod is negatively charged, free electrons move to the side of the sphere opposite the side with the rod. If the rod is positively charged, the free electron moves to the side of the sphere with the rod. In either case, the region of the sphere near the rod acquires a charge with the sign opposite to that on the rod.

a. Since opposedly charged objects always attract each other, the rod and ball always experience mutual attractive forces.

b. Since the side of the sphere near the bar always has the opposite charge to the charge of the rod, the rod and the sphere always attract each other. <span>They do not repel each other.</span></span>

3 0

3 years ago