Answer:
2.32 s
Explanation:
Using the equation of motion,
s = ut+g't²/2............................ Equation 1
Where s = distance, u = initial velocity, g' = acceleration due to gravity of the moon, t = time.
Note: Since Onur drops the basket ball from a height, u = 0 m/s
Then,
s = g't²/2
make t the subject of the equation,
t = √(2s/g')...................... Equation 2
Given: s = 10 m, g' = 3.7 m/s²
Substitute this value into equation 2
t = √(2×10/3.7)
t = √(20/3.7)
t = √(5.405)
t = 2.32 s.
Answer:
22145.27733 ft
124984.76055 ft
Explanation:
The equation of pressure is
where,
=Atmospheric pressure = 800 mbar
k = Constant
h = Altitude = 35000 ft
Now
The altitude will be 22145.27733 ft
The elevation is 124984.76055 ft
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