Answer:
Given the area A of a flat surface and the magnetic flux through the surface
it is possible to calculate the magnitude
.
Explanation:
The magnetic flux gives an idea of how many magnetic field lines are passing through a surface. The SI unit of the magnetic flux
is the weber (Wb), of the magnetic field B is the tesla (T) and of the area A is (
). So 1 Wb=1 T.m².
For a flat surface S of area A in a uniform magnetic field B, with
being the angle between the vector normal to the surface S and the direction of the magnetic field B, we define the magnetic flux through the surface as:
![\Phi=B\ A\ cos\theta](https://tex.z-dn.net/?f=%5CPhi%3DB%5C%20A%5C%20cos%5Ctheta)
We are told the values of
and B, then we can calculate the magnitude
![\frac{\Phi}{A}=B\ cos\theta](https://tex.z-dn.net/?f=%5Cfrac%7B%5CPhi%7D%7BA%7D%3DB%5C%20cos%5Ctheta)
Answer:
Explanation:
initial velocity u = 32.7 m /s
final velocity v = 50.3 m /s
displacement s = 44500 m
acceleration a = ?
v² = u² + 2 a s
50.3² = 32.7² + 2 x a x 44500
2530.09 = 1069.29 + 89000a
a .016 m /s²
time taken t = ?
v = u + at
50.3 = 32.7 + .016 t
t = 1100 s
Answer:
The ball doesn't strike the building because it strikes the ground at d=1.62 meters.
Explanation:
V= 5 m/s < 70º
Vx= 1.71 m/s
Vy= 4.69 m/s
h= Vy * t - g * t²/2
clearing t for the flying time of the ball:
t= 0.95 s
d= Vx * t
d= 1.62 m
Explanation:
Given that,
Wavelength of the light, ![\lambda=4170\ A=4170\times 10^{-10}\ m](https://tex.z-dn.net/?f=%5Clambda%3D4170%5C%20A%3D4170%5Ctimes%2010%5E%7B-10%7D%5C%20m)
Work function of sodium, ![W_o=4.41\times 10^{-19}\ J](https://tex.z-dn.net/?f=W_o%3D4.41%5Ctimes%2010%5E%7B-19%7D%5C%20J)
The kinetic energy of the ejected electron in terms of work function is given by :
![KE=h\dfrac{c}{\lambda}-W_o\\\\KE=6.63\times 10^{-34}\times \dfrac{3\times 10^8}{4170\times 10^{-10}}-4.41\times 10^{-19}\\\\KE=3.59\times 10^{-20}\ J](https://tex.z-dn.net/?f=KE%3Dh%5Cdfrac%7Bc%7D%7B%5Clambda%7D-W_o%5C%5C%5C%5CKE%3D6.63%5Ctimes%2010%5E%7B-34%7D%5Ctimes%20%5Cdfrac%7B3%5Ctimes%2010%5E8%7D%7B4170%5Ctimes%2010%5E%7B-10%7D%7D-4.41%5Ctimes%2010%5E%7B-19%7D%5C%5C%5C%5CKE%3D3.59%5Ctimes%2010%5E%7B-20%7D%5C%20J)
The formula of kinetic energy is given by :
![KE=\dfrac{1}{2}mv^2\\\\v=\sqrt{\dfrac{2KE}{m}} \\\\v=\sqrt{\dfrac{2\times 3.59\times 10^{-20}}{9.1\times 10^{-31}}} \\\\v=2.8\times 10^5\ m/s](https://tex.z-dn.net/?f=KE%3D%5Cdfrac%7B1%7D%7B2%7Dmv%5E2%5C%5C%5C%5Cv%3D%5Csqrt%7B%5Cdfrac%7B2KE%7D%7Bm%7D%7D%20%5C%5C%5C%5Cv%3D%5Csqrt%7B%5Cdfrac%7B2%5Ctimes%203.59%5Ctimes%2010%5E%7B-20%7D%7D%7B9.1%5Ctimes%2010%5E%7B-31%7D%7D%7D%20%5C%5C%5C%5Cv%3D2.8%5Ctimes%2010%5E5%5C%20m%2Fs)
Hence, this is the required solution.
Velocity is displacement/time
(Displacement is the overall change in distance)
So you’ll want to divide 200 by 25, which should give you:
8 m/s