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xeze [42]
4 years ago
10

In the compound below, what do the subscripts indicate?

Physics
2 answers:
mihalych1998 [28]4 years ago
5 0

Answer:

b

that's how equations are

Effectus [21]4 years ago
4 0

Answer:

There are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms in this compound

Explanation:

The subscript in C6H12O6 indicates there are 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms in this compound. The compound contains Carbon, Hydrogen and Oxygen atoms. The compound depicts the molecular formula of Glucose (a simple sugar) and also a monosaccharide .

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The heating of groundwater forms
KIM [24]
The appropriate answer is c. geysers. A geysers a hot water fountain that spouts intermittently with great force, frequently accompanied by a thunderous roar. The world famous Old Faithful is located in Yellowstone National Park. This geyser erupts every 65 min sending a jet of water almost 60 meters into the air. Sinkholes and caves are formed by the action of groundwater on carbonate rocks which causes them to colapse and former these structures.
6 0
3 years ago
Read 2 more answers
Will mark as brainlist for only correct answer
Crank

Answer:

low, low

Explanation:

Longer wavelengths will have lower frequencies, and shorter wavelengths will have higher frequencies.

Large amplitude waves contain more energy. The other is frequency, which is the number of waves that pass by each second. If more waves( or more wiggly lines)  pass by, more energy is transferred each second

4 0
3 years ago
Which prefix represents hundredths in the metric system?
Volgvan

The prefix your looking for is centi as in centimeter. I got this answer on google.

So please mark me as Brainiest.

3 0
3 years ago
Does coefficient of thermal expansion vary with temperature?
N76 [4]

Answer:

yes

Explanation:

8 0
3 years ago
A hydrogen atom in a galaxy moving with a speed of 6.65×106 m/???? away from the Earth emits light with a wavelength of 5.13×10−
Mumz [18]

Answer:

The observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m.

Explanation:

Given that,

The actual wavelength of the hydrogen atom, \lambda_a=5.13\times 10^{-7}\ m

A hydrogen atom in a galaxy moving with a speed of, v=6.65\times 10^6\ m/s

We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :

v=c\times \dfrac{\lambda_o-\lambda_a}{\lambda_a}

\lambda_o is the observed wavelength

\lambda_o=\dfrac{v\lambda_a}{c}+\lambda_a\\\\\lambda_o=\dfrac{6.65\times 10^6\times 5.13\times 10^{-7}}{3\times 10^8}+5.13\times 10^{-7}\\\\\lambda_o=5.24\times 10^{-7}\ m

So, the observed wavelength on Earth from that hydrogen atom is 5.24\times 10^{-7}\ m. Hence, this is the required solution.

8 0
3 years ago
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