3 years ago

Every few years, Earth passes through Saturn’s rings.

Physics

1 answer:

creativ13 [48]3 years ago

3 0

Answer:

Fales its impossibke bc they r so far apart

Explanation:

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A small lightbulb is 1.06 m from a screen. A) If you have a convex lens with 20 cm focal length, where are the two lens location

MatroZZZ [7]

Answer:

A)Explanation:

Let object distance be u.

Image distance v = 1.06 - u

Focal length = 20 cm = .2 m

Applying lens formula

1 / v - 1 / u = 1 / f

1 /( 1.06-u) - 1 / u = 1 / .2

5 u² -3.3u - 1.06 =0

It will have two roots

u₁ = .1636 m, u₂ = .8964 m

B ) Magnification

= u = .1636m , v = .8964m

m = .8964 / .1636 = 5.48

C ) When u = .8964m ,v = .1634m

m = .1634 / .8964

=.182

7 0

3 years ago

Ashley decides to enter her pet turtle in a race. She knows her turtle can travel at a rate of 2 meters per hour. The race track

Genrish500 [490]

It would probably be B

7 0

3 years ago

A car traveling at 30 m/s drives off a cliff that is 50 meters high? How far away does it land?

Semenov [28]

Answer:

The maximum range $R_{max}= 132. 72$ m

Explanation:

Given,

The initial velocity of the car, u = 30 m/s

The height of the cliff, h = 50 m

Let the car drives off the cliff with a horizontal velocity of 30 m/s.

The formula for a projectile that is projected from a height h from the ground is given by the relation

$R_{max}= \frac{u}{g}\sqrt{u^{2} + 2gh }$ m

Where,

g - acceleration due to gravity

Substituting the values in the above equation

$R_{max}= \frac{30}{9.8}\sqrt{30^{2} + 2X9.8X50 }$

= 132.72 m

Hence, the car lands at a distance, $R_{max}= 132. 72$ m

3 0

4 years ago

Second and third class levers are differentiated by __________.

ira [324]

Answer:

i think it is b

hope this helps

Explanation:

5 0

4 years ago

Read 2 more answers

An object at rest starts accelerating.

Shalnov [3]

Answer:

<u>We are given: </u>

initial velocity (u) = 0 m/s

final velocity (v) = 10 m/s

displacement (s) = 20 m

acceleration (a) = a m/s/s

<u>Solving for 'a'</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(10)² - (0)² = 2(a)(20)

100 = 40a

a = 100 / 40

a = 2.5 m/s²

6 0

3 years ago