Answer:BaCl (aq)+ K2CO3 (aq)——> Ba2CO3 (aq) + KCl (aq)
Explanation:
The equation is already balanced and it is a double replacement reaction.
The answer is B
To write the equilibrium constant for an equation, all you have to do is divide the products by the reactants. The reactants are always on the left side, and the products are always on the right side. The coefficients of the elements will be written as the exponent of that same element. However, in this equation, we do not have to write any exponents, as there are no coefficient but 1.
Answer:
No solution
Explanation:
This is only 4 sig digits
The balanced equation for the reaction between NaOH and HCl is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
number of NaOH moles reacted - 0.1 mol/L x 0.054 L = 0.0054 mol
number of HCl moles reacted = number of NaOH moles reacted
since the molar ratio of acid to base is 1:1
therefore number of HCl moles reacted - 0.0054 mol
the number of moles of HCl in 125 mL - 0.0054 mol
therefore number of HCl moles in 1000 mL - 0.0054 mol / 125 mL x 1000 mL
number of moles of solute in 1000 mL is known as the molarity concentration
concentration of HCl is 0.0432 M
It’s c because a wave cycle is repeating patterns all over again and again
