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2 years ago

Which of the following happen because of an increase in thermal energy/temperature? (Select all that apply)

Chemistry

2 answers:

swat322 years ago

7 0

A b c , i think ...

Nataliya [291]2 years ago

6 0

Vaporization melting and condensation

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Does the following statement describes a function of DNA, a function of RNA, of both DNA and RNA, or a function of neither DNA o

steposvetlana [31]

Guy that said it was DNA was right i just took the test to so another words your answer is Letter A DNA have a nice weekend! <span />

4 0

3 years ago

Read 2 more answers

Answer please and thank you

Alex73 [517]

Answer:

Option B. 30 KJ.

Explanation:

The following data were obtained from the question:

Temperature (T) = 5000 K

Enthalpy change (ΔH) = – 220 kJ/mol

Change in entropy (ΔS) = – 0.05 KJ/mol•K

Gibbs free energy (ΔG) =...?

The Gibbs free energy, ΔG can be obtained by using the following equation as illustrated below:

ΔG = ΔH – TΔS

ΔG = – 220 – (5000 x – 0.05)

ΔG = – 220 – (– 250)

ΔG = – 220 + 250

ΔG = 30 KJ

Therefore, the Gibbs free energy, ΔG is 30 KJ.

3 0

3 years ago

What volume will 1.12 moles of nitrogen gas occupy at STP

krok68 [10]

Answer:

Explanation:

Volume occupied by Nitrogen gas at STP = number of moles x 22.4dm³/mol

Number of moles = 1.12moles

Volume = 1.12 x 22.4

Volume at STP = 25.1dm³

8 0

3 years ago

The problems explain what I need, I also need the work shown or explained at the least

PtichkaEL [24]

Answer:

Q1/0.83L

Q2/ 6.606L

Q3/ 3.27L

Explanation:

All the question Charles law for ideal gases

And his law up right there ☝️

3 0

2 years ago

9.27 mol of oxygen is equal to______molecules of oxygen <br> Please help I need it

bixtya [17]

<h3>Answer:</h3>

5.58 × 10²⁴ molecules O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

9.27 mol O₂ (Oxygen)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 9.27 \ mol \ O_2(\frac{6.022 \cdot 10^{23} \ molecules \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 5.58239 \cdot 10^{24} \ molecules \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules. We are given 3 sig figs.</em>

5.58239 × 10²⁴ molecules O₂ ≈ 5.58 × 10²⁴ molecules O₂

8 0

2 years ago