Answer:
In the 1H NMR spectrum of ethanol three different signals are observed, this is due to the existence of 3 types of hydrogens with different chemical environment. Hydrogens A (3.57 ppm) are more screened than C (1.10 ppm) due to the presence of oxygen (electonegative atom that removes electron density). The chemical environment of hydrogen B (4.78 ppm), attached directly to oxygen, is also different by resonating at a frequency different from the previous ones.
The hydroxylic hydrogen produces a singlet, the pair of carbon hydrogens one give rise to a quadruplet and the three hydrogens of carbon two produce a triplet.
Explanation:
Answer:
d sub level starts from the 3rd energy level; means you can see electrons in d sub level in any energy levels after third one.
So the answer is "In any energy levels ≥ 3"
A simple information ; s sub level is in any energy level,
p sub level is in any energy level beginning from the 2nd energy level,
d sub level appears ≥ 3rd energy level
f sub level appears in 4th energy level and over.
Hope it helps!
#MissionExam001
Answer:
2.39×10¯⁵ m²
Explanation:
From the question given above, the following data were obtained:
Distance (d) = 8.08×10¯⁵ m
Charge (q) = 2.24×10¯⁹ C
Potential difference = 855 V
Area(A) =?
NOTE: Permittivity (ε₀) = 8.854×10¯¹² F/m
The area can be obtained as follow:
q = ε₀AV/d
2.24×10¯⁹ = 8.854×10¯¹² × A × 855 / 8.08×10¯⁵
2.24×10¯⁹ = 7.57×10¯⁹ × A / 8.08×10¯⁵
Cross multiply
7.75×10¯⁹ × A = 2.24×10¯⁹ × 8.08×10¯⁵
7.75×10¯⁹ × A = 1.81×10¯¹³
Divide both side by 7.75×10¯⁹
A = 1.81×10¯¹³ / 7.75×10¯⁹
A = 2.39×10¯⁵ m²
Thus, the area of the plate is 2.34×10¯⁵ m²
The reaction between LiOH and HCl is;
LiOH + HCl → LiCl + H₂O
The stoichiometric ratio between LiOH and HCl is 1 : 1
moles of LiOH added = moles of HCl needed to neutralize.
Molar mass of LiOH = 24 g/mol
moles = mass / molar mass
LIOH moles = 1.65 / 24 = 0.06875 mol
Hence needed HCl moles = 0.06875 mol
Molarity = moles (mol) / Volume (L)
Hence needed HCl volume = moles / molarity
= 0.06875 mol / 0.150 mol/L
= 0.458 L = 458 mL
Answer:
c Acid + base = conjugate base + conjugate acid
Explanation:
In a Bronsted-Lowry acid-base reaction, the original acid gives up its proton and becomes a conjugate base. In like manner, the original base accepts a proton and becomes a conjugate acid. For every acid, there is a conjugate base and for every base, there is a conjugate acid:
HA ⇄ H⁺ + A⁻
acid conjugate base
B + H⁺ ⇄ HB⁺
base conjugate acid
