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3 years ago

Guys please answer!!!! why is mirage is formed and what cause of it

1 answer:

4 0

Mirages are natural illusions that happen because of bending light rays that in turn creates a shifted image in the distance or sky. There are types of mirages like the inferior mirage which the observer sees bluish land that looks like water. Inferior mirages happen because light rays from the sky or the object travel the same air layers and bend the same amount too. Heat haze is an inferior mirage and happens you see objects through layer of heat gas or air often happening on the road. Superior mirages occur when there's a cooler level of air lower than a warmer level of air, on polar areas or icy landscapes.

Sorry it's a bit wordy :)

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An airplane is flying from Dallas, Texas to Pensacola, Florida. Flying at maximum velocity, it encounters strong winds moving at

jenyasd209 [6]

Answer:

G. It will take twice as long.

Explanation:

Let's call $v$ the original speed of the plane and $d$ the distance between Dallas and Pensacola. The time the plane originally takes to complete the flight is

$t=\frac{d}{v}$

In this problem, we are told that the plane encounters wind moving at half of its speed: $\frac{v}{2}$ , in the opposite direction. This means that the new speed of the plane is

$v'=v-\frac{v}{2}=\frac{v}{2}$

And so, the time the plane takes now to complete the flight is

$t'=\frac{d}{v/2}=2\frac{d}{v}=2t$

So, the plane takes twice the time as before.

4 0

3 years ago

A skater with a mass of 72 kg is traveling east at 5.8 m/s when he collides with another skater of mass 45 kg heading 60° south

Akimi4 [234]

The final velocity is 5.87 m/s

<u>Explanation:</u>

Given-

mass, $m_{1}$ = 72 kg

speed, $v_{1}$ = 5.8 m/s

$Mass_{2}$ , $m_{2}$ = 45 kg

$speed_{2}$ , $v_{2}$ = 12 m/s

Θ = 60°

Final velocity, v = ?

Applying the conservation of momentum:

$m_{1}$ X $v_{1}$ + $m_{2}$ X $v_{2}$ = ( $m_{1}$ + $m_{2}$ ) v

72 X 5.8 + 45 X 12 X cos 60° = (72 + 45) v

v = 417.6 + 540 X $\frac{0.5}{117}$

v = 417.6 + $\frac{270}{117}$

v = 5.87 m/s

The final velocity is 5.87 m/s

8 0

3 years ago

The first electric generators used direct current, so they needed to be reversed manually on a regular basis in order to work pr

djyliett [7]

Could I see the questions

4 0

3 years ago

The volume occupied by a sample of gas is 480 mL when the pressure is 115 kPa.What pressure must be applied to the gas to make i

balandron [24]

Answer:

The answer is

Explanation:

Using Boyle's law to find the final pressure

That's

$P_1V_1 = P_2V_2$

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final pressure

$P_2 = \frac{P_1V_1}{V_2}$

From the question

P1 = 115 kPa

V1 = 480 mL

V2 = 650 ml

So we have

$P_2 = \frac{115000 \times 480}{650} = \frac{55200000}{650} \\ = 84923.076923...$

We have the final answer as

Hope this helps you

7 0

3 years ago

To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3

hodyreva [135]

Answer : The correct option is, (c) $3.7\times 10^2J/^oC$

Explanation :

First we have to calculate the energy or heat.

Formula used :

$E=V\times I\times t$

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

$E=(3.6V)\times (2.6A)\times (350s)$

$E=3276J$

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

$C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}$

where,

C = heat capacity of the calorimeter

$T_{initial}$ = initial temperature = $20.3^oC$

$T_{final}$ = final temperature = $29.1^oC$

Now put all the given values in this formula, we get:

$C=\frac{3276J}{(29.1-20.3)^oC}$

$C=372.27J/^oC=3.7\times 10^2J/^oC$

Therefore, the heat capacity of the calorimeter is, $3.7\times 10^2J/^oC$

7 0

3 years ago