Answer:
15.13 m/s
Explanation:
The wave speed of the stretched rope can be calculated using the following formula
where is the tension on the rope and
is the density of the rope per unit length
How do you solve
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1 answer:
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Let be the acceleration of the masses. By Newton's second law, we have
• for the masses on the left,
where is the magnitude of tension in the pulley cord, and
• for the mass on the right,
Eliminate to get
Starting from rest and accelerating uniformly, the right-hand mass moves up 75 cm = 0.75 m and attains an upward velocity such that
When the 0.5m mass is released, the new net force equations change to
• for the mass on the right,
where and
are still tension and acceleration, but not having the same magnitude as before the mass was removed; and
• for the mass on the left,
Eliminate .
Now, the right-hand mass has an initial upward velocity of , but we're now treating down as the positive direction. As it returns to its starting position, its speed
at that point is such that