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Ksju [112]
3 years ago
15

What outside force prevents the planets from moving in a straight line into space

Physics
2 answers:
slamgirl [31]3 years ago
6 0

Ah hah !  That's the gravitational force between the sun
and each planet.

One of the many things that would be different without
gravity is:  There would be no orbits.
Harrizon [31]3 years ago
6 0
Gravity is what causes the planets to stay in there revolution, and what causes them to not drift into space. hope I helped:)
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A wire, 1.0 m long, with a mass of 90 g, is under tension. A transverse wave is propagated on the wire, for which the frequency
Mice21 [21]

Answer:

T = 712.9 N

Explanation:

First, we will find the speed of the wave:

v = fλ

where,

v = speed of the wave = ?

f = frequency = 890 Hz

λ = wavelength = 0.1 m

Therefore,

v = (890 Hz)(0.1 m)

v = 89 m/s

Now, we will find the linear mass density of the wire:

\mu = \frac{m}{L}

where,

μ = linear mass density of wie = ?

m = mass of wire = 90 g = 0.09 kg

L = length of wire = 1 m

Therefore,

\mu = \frac{0.09\ kg}{1\ m}

μ = 0.09 kg/m

Now, the tension in wire (T) will be:

T = μv² = (0.09 kg/m)(89 m/s)²

<u>T = 712.9 N</u>

7 0
2 years ago
The electric field between two parallel plates connected to a 45-volt battery is 500. volts per meter. The distance between the
kotykmax [81]
Electric field = potential difference
                       -----------------------------
                        distance between plates
 
 Distance between plates   =         45
                                                  ----------
                                                     500
 
                                           =          0.09 meters.

8 0
3 years ago
Two students make the following claims:
antiseptic1488 [7]

Answer:

E. Student 1 is correct, because as θ is increased, h is the same.

Explanation:

Here we have the object of a certain mass falling under gravity so the force acting on the it will depend on mass of the object and the acceleration due to gravity.

Mathematically:

F=m.g

As we know that the work done is evaluated as the force applied on a body and the displacement of the body in the direction of the force.

And for work we have:

W=F.s\cos\theta

where:

s= displacement of the object

\theta= angle between the force and displacement vectors

Given that the height of the object is same in each trail of falling object under the gravity be it a free-fall or the incline plane.

  • In case of free-fall the angle between the force is and the displacement is zero.
  • In case when the body moves along the inclined plane the force applied by the gravity is same because it depends upon the mass of the object. And the net displacement in the direction of the gravitational force is the height of the object which is constant in both the cases.

So, the work done by the gravitational force is same in the two cases.

6 0
3 years ago
A 100-n force has a horizontal component of 80 n and a vertical component of 60 n. the force is applied to a box which rests on
iragen [17]
<span>160 Joules

   For this problem, we can ignore the vertical component of the applied force and focus on only the horizontal component of 80 N and since work is defined as force over distance, let's multiply the force by the distance: 80 N * 2.0 m = 160 Nm = 160 kg*m^2/s^2 = 160 Joules.

   So the cart has a final kinetic energy of 160 Joules.</span>
6 0
3 years ago
If a person is 6.25 m away from a 60.0 w speaker, what is the sound level they are hearing?
vodka [1.7K]

Answer:

110.87 dB

Explanation:

(I got it right on Acellus)

I= P/4(pi)r^2 = 60/4(pi)6.25^2

60/4(pi)6.25^2=0.12223

B=10log(I/Io)

B=10log(0.12223/1*10^-12) = 110.87 dB

111 in sigfigs

4 0
2 years ago
Read 2 more answers
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