All of these metals from cations, so they lost electrons when forming ions. The answer is D.
Answer:
If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia
Explanation:
Step 1: Data given
Mass of nitrogen gas (N2) = 13.4 grams
Molar mass of N2 = 28 g/mol
Molar mass of NH3 = 17.03 g/mol
Step 2: The balanced equation
N2 + 3H2 → 2NH3
Step 3: Calculate moles of N2
Moles N2 = Mass N2 / molar mass N2
Moles N2 = 13.4 grams / 28.00 g/mol
Moles N2 = 0.479 moles
Step 4: Calculate moles of NH3
For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3
For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles
Step 5: Calculate mass of NH3
Mass of NH3 = moles NH3 * molar mass NH3
Mass NH3 = 0.958 moles * 17.03 g/mol
Mass NH3 = 16.3 grams
If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia
Answer : The amount of water lost was, 333.4 grams.
Explanation : Given,
Heat released = 753480 J
Formula used :
where,
Q = heat released = 753480 J
m = mass = ?
L = latent heat vaporization of water = 
Now put all the given values in the above formula, we get:
Thus, the amount of water lost was, 333.4 grams.
The atomic number of Cu = 29
Valence electron configuration of Cu = 3d¹⁰4s¹
Cu+ is formed when 1 electron is lost from Cu. Therefore, the atomic number for Cu+ = 28
Similarly, loss of 2 electrons from Cu results in Cu2+ with an atomic number = 27
Cu+ is the larger ion. This is because as electrons are removed from the valence orbitals, the attraction between the outer electrons and the nucleus tends to increase which then results in a decrease in size.
Ans: Cu+ has one more electron
