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suter [353]
3 years ago
12

Which of the following is not considered an alternative source of energy?

Physics
1 answer:
SCORPION-xisa [38]3 years ago
3 0
The answer is d. Natural gas
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The work done on an elevator that has a mass of 1000kg and lifted 4m in 10 seconds is how many joules.
GaryK [48]

Answer:

39,200 Joules

3920 watts

Explanation:

5 0
4 years ago
If a weightlifter used 1,200 newtons of force to lift a barbell to a height of 2.5 meters in 3 seconds, how much work did he do?
Blizzard [7]
C.)  Work done = Force x displacement = 1200 x 2.5 = 3000 J. Hope this helps!
3 0
3 years ago
A hill that has a 36.1% grade is one that rises 36.1 m vertically for every 100.0 ml of distance in the horizontal direction. At
GaryK [48]

Answer:

angle is 19.85°

Explanation:

given data

grade = 36.1 %

vertically distance y = 36.1 m

horizontal distance x = 100 m

to find out

angle

solution

we know that according to question here

it make a triangle shape that contain 100 m base and height 36.1 m

and make angle with base is θ

so by triangle we know here

tanθ = y/x   ..........1

so we now put x and y and find θ

tanθ = 36.1 / 100

tanθ = 0.361

θ = 19.85°

so angle is 19.85°

7 0
3 years ago
What is quantum programing
Komok [63]

Answer: Quantum programming is the process of assembling sequences of instructions, called quantum programs, that are capable of running on a quantum computer. Quantum programming languages help express quantum algorithms using high-level constructs.

Explanation:

7 0
4 years ago
A 75.0-kg person is riding in a car moving at 20.0 m/s when the car runs into a bridge abutment. (a) calculate the average force
iragen [17]

(a) -1.5\cdot 10^6 N

First of all, we need to calculate the acceleration of the person, by using the following SUVAT equation:

v^2 -u ^2 = 2ad

where

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d = 1.00 cm = 0.01 m is the displacement of the person

Solving for a,

a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.01)}=-20000 m/s^2

And the average force on the person is given by

F=ma

with m = 75.0 kg being the mass of the person. Substituting,

F=(75)(-20000)=-1.5\cdot 10^6 N

where the negative sign means the force is opposite to the direction of motion of the person.

b) -1.0\cdot 10^5 N

In this case,

v = 0 is the final velocity

u = 20.0 m/s is the initial velocity

a is the acceleration

d  = 15.00 cm = 0.15 m is the displacement of the person with the air bag

So the acceleration is

a=\frac{v^2-u^2}{2d}=\frac{0-20.0^2}{2(0.15)}=-1333 m/s^2

So the average force on the person is

F=ma=(75)(-1333)=-1.0\cdot 10^5 N

7 0
4 years ago
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