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harkovskaia [24]
3 years ago
5

Given the function f(x) = 3 x - 21 + 6, for what values of x is f(x) = 18?

Mathematics
2 answers:
weqwewe [10]3 years ago
5 0
18=3x-21+6
18=3x-15
33=3x
X=11
IrinaK [193]3 years ago
4 0

Answer:

X=2

If 21+6=27 then subtract what f(x) is (which is 18) from the 27. 27-18=6 then 3x2=6 so therefore your answer is 2. Hope this helps!!

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vampirchik [111]

Step-by-step explanation:

3(x+4) ≤ 36

3x + 12 ≤ 36

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x ≤ 8

4 0
1 year ago
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6 divided by 2 (1+2) = ?
labwork [276]

Answer:

6/2 (1+2) = 9

Step-by-step explanation:

6/2 (1+2)

Order of operations PEMDAS

Parentheses first 6/2(3)

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3 years ago
Eric Drew an obtuse triangle. Which of the following could be true for Eric's triangle.
Vika [28.1K]

Answer:

<u>Option:B</u> is the correct answer.

B: possible angle measures of the triangle are 92, 48, and 40 .

Step-by-step explanation:

We know that an obtuse triangle is a triangle whose one angle is a obtuse angle ( i.e. the measure of the angle is greater than 90 degree and less than 180 degrees).

A)

A: all three angles have equal measures

Let the angle of a triangle be 'x'.

As we know that the sum of all the angles of a triangle is 180°.

This implies that:

x+x+x=180°

3x=180°

⇒ x=60°

Hence, the triangle will not be obtuse as none of the angle is obtuse.

Hence, option: A is incorrect.

B)

possible angle measures of the triangle are 92, 48, and 40.

This option is correct.

Since there is one angle which is obtuse ( measure 92 degree)

and also such a angle measure is possible in a triangle as sum of all the angles is 180°.

( since 92+48+40=180°)

C)

two of the angles are equal, and the third angle has a measure of 70.

Let the equal angles be represented by 'x'.

As the sum of all the angles is 180°.

⇒   x+x+70=180°

⇒ 2x=110°

⇒  x=55°

Hence, here also none of the angle is obtuse.

hence, option: C is incorrect.

D)

One angle has a measure of 90, while, the other two angles measure less than 90°.

Such a triangle will not be a obtuse triangle as none of the angle measure is greater than 90°.

Hence, option: D is incorrect.

4 0
3 years ago
Does a charge battery have potential energy
vovangra [49]
I’m pretty sure it has potential energy. Because a charge battery can be charged. So it can have energy
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3 years ago
Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

Thus, a Normal distribution can be applied to approximate the distribution of the alumni ratings.

7 0
3 years ago
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