1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Licemer1 [7]
3 years ago
10

The molar mass of V2O3 is A. 66.94 B. 133.88 C. 149.88 D. 200.82

Chemistry
1 answer:
enot [183]3 years ago
4 0
B. 133.88
Sorry po kung mali
You might be interested in
3 points
vfiekz [6]

Answer:

density=6.74g/ml

:320g÷47.5ml

d=6.74g/ml

thank you

<em><u>I </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this </u></em><em><u>is </u></em><em><u>helpful</u></em>

8 0
3 years ago
Which organisms in the food web shown compete for the same food source in this environment?
11111nata11111 [884]

Answer:

there is no photo

Explanation:

3 0
2 years ago
10 In a bond between an atom of carbon and an atom of fluorine, the fluorine atom has a
Oksanka [162]
The best answer is (2) <span>stronger attraction for electrons, for the fluorine atom has a higher electronegativity than the carbon one, if not highest of all nonmetals.
Hope this helps~</span>
4 0
3 years ago
Which of the following describe chemical properties
alexandr1967 [171]
Chemical properties are all those properties that are shown when the chemical is a part of a reaction or is changed in any way. Unlike physical properties, they affect the composition of the chemical and the way it behaves, while physical does not change the chemical itself. Such properties are toxicity, flammability, reaction with other elements, stability, and many more.
3 0
3 years ago
Calculate the pH for each of the following cases in the titration of 25.0 mL of 0.150 M acetic acid (Ka = 1.75x10-5) with 0.150
mylen [45]

Answer:

a) pH = 2.793

b) pH = 4.280

c) pH = 4.933

d) pH = 8.816

e) pH = 8.861

f) pH = 8.891

Explanation:

a) VNaOH = 0 mL

∴ CH3COOH ↔ CHECOO- + H3O+

⇒ Ka = 1.75 E-5 = [ H3O+ ] * [ CH3COO-] / [ CH3COOH ]

mass balance:

⇒ <em>C</em> CH3COOH = [ CH3COO- ] + [ CH3COOH ] = 0.150 M

charge balance:

⇒ [ H3O+ ] = [ CH3COO- ]

⇒ Ka = 1.75 E-5 = [ H3O+ ]² / ( 0.150 M - [ H3O+ ] )

⇒ [ H3O+ ]² + 1.75 E-5 [ H3O+ ] - 2.625 E-6 = 0

⇒ [ H3O+ ] = 1.61146 E-3 M

⇒ pH = - Log [ H3O+ ] = 2.793

b) after  5.0 mL NaOH:

∴ CH3COOH + NaOH ↔ CH3COONa + H2O

⇒ <em>C</em> NaOH = (5 E-3 L * 0.150 mol/L) / (0.025+0.01 ) = 0.02143 M

⇒ <em>C</em> CH3COOH = ((0.025*0.150) - (0.01*0.150)) / (0.025 + 0.01) = 0.0643 M

mass balance:

⇒ 0.02143 + 0.0643 = [ CH3COOH ] + [ CH3COO- ] = 0.086 M

charge balance:

⇒ [ H3O+ ] + [Na ] = [ CH3COO- ]

⇒ [ H3O+ ] + 0.02143 = [ CH3COO- ]

⇒ Ka = [ H3O+ ] * ( [ H3O+ ] + 0.150 ) / (0.086 - 0.02143 - [ H3O+ ]) = 1.75 E-5

⇒ [ H3O+ ]² + 0.02143 [ H3O+ ] = 1.13 E-6 - 1.75 E-5 [ H3O+ ]

⇒ [ H3O+ ]² + 0.02144 [ H3O+ ] - 1.13 E-6 = 0

⇒ [ H3O+ ] = 5.26 E-5 M

⇒ pH = 4.28

c) after 15 mL NaOH:

⇒ <em>C</em> CH3COOH = 0.0375 M

⇒ <em>C</em> NaOH = 0.05625 M

mass balance:

⇒ 0.09375 M = [ CH3COO- ] +[ CH3COOH ]

charge balance:

⇒ [ H3O+ ] + 0.05625 = [ CH3COO- ]

⇒ Ka = 1.75 E-5 = [ H3O+ ] * ([ H3O+ ] + 0.05625) / (0.09375 - 0.05625 - [H3O+])

⇒ [H3O+]² + 0.05625[H3O+] = 6.5625 E-7 - 1.75 E-5 [H3O+]

⇒ [ H3O+]² + 0.05626[H3O+] - 6.5625 E-7 = 0

⇒ [ H3O+ ] = 1.1662 E-5 M

⇒ pH = 4.933

d) after 25 mL NaOH:

⇒ <em>C </em>NaOH = 0.075 M

⇒ <em>C</em> CH3COOH = 0 M....equiv. point

⇒Kh = Kw/Ka = 1 E-14 / 1.75 E-8 = 5.7143 E-10 = [ OH-]² / ( 0.075 - [OH-])

⇒ [OH-]² + 5.7143 E-10[OH-] - 4.286 E-11 = 0

⇒ [ OH- ] = 6.5463 E-6 M

⇒ pOH = 5.184

⇒ pH = 8.816

e) after 40 mL NaOH:

⇒ <em>C </em>NaOH = 0.0923 M

⇒ [OH-]² + 5.7143 E-10 [OH-] - 5.275 E-11 = 0

⇒ [OH-] = 7.2624 E-6 M

⇒ pOH = 5.139

⇒ pH = 8.861

f) after 60 mL NaOH:

⇒ <em>C </em>NaOH = 0.106 M

⇒ [OH-]² + 5.7143 E-10 [OH-] - 6.05 E-11 = 0

⇒ [OH-] = 7.7782 E-6 M

⇒ pOH = 5.11

⇒ pH = 8.891

5 0
3 years ago
Other questions:
  • Can u help?? It's science and I'm in 6th grade
    15·1 answer
  • Which of the following is accurate in describing the placement and classification of iodine?
    13·1 answer
  • Which element is likely to be the most reactive?
    15·2 answers
  • II. Binding Forces A. Write a brief, one or two sentence, description of each binding force listed below. 1. London dispersion f
    14·1 answer
  • Jupiters atmosphere is mostly made of ___
    8·1 answer
  • When an aqueous solution at room temperature is analyzed, the [H+] is found to be 2.0 × 10−3 M. What is the [OH−]?
    5·2 answers
  • What is the charge of 5protons 6 neutrons and 5 electrons
    9·1 answer
  • Helppp nowwww plsss
    13·1 answer
  • a sample of compound determined to contain 1.71 g C and 0.287 g H. The corresponding empirical formula is
    7·1 answer
  • 3. Students measured the mass of the reactants and products for a combustion reaction they observed.
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!