Answer:
3Na2SO4
Explanation:
 3Na2SO4
# of molecules: 3 moles of Na2SO4 or 3 × 6.22 × 10^23 molecules. 
# of elements: 3 elements l
Name of element: = Sodium, S = Sulphur, O = Oxygen
# of atoms: Na = 6 atoms, S= 3, O= 12
Total # of atoms: 21
The #3 is a Coefficient. 
Please mark branliest if you are satisfied. Thanking in anticipation. 
 
        
             
        
        
        
A 20 L sample of the gas contains 8.3 mol N₂.
According to <em>Avogadro’s Law,</em> if <em>p</em> and <em>T</em> are constant
<em>V</em>₂/<em>V</em>₁ = <em>n</em>₂/<em>n</em>₁
<em>n</em>₂ = <em>n</em>₁ × <em>V</em>₂/<em>V</em>₁
___________
<em>n</em>₁ = 0.5 mol; <em>V</em>₁ = 1.2 L
<em>n</em>₂ = ?;           <em>V</em>₂ = 20 L
∴<em>n</em>₂ = 0.5 mol × (20 L/1.2 L) = 8.3 mol
 
        
             
        
        
        
<h3>
Answer:</h3>
9 mol H₂O
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>  
<u>Pre-Algebra</u>  
Order of Operations: BPEMDAS  
- Brackets
 - Parenthesis
 - Exponents
 - Multiplication
 - Division
 - Addition
 - Subtraction
 
<u>Chemistry</u>  
<u>Atomic Structure</u>  
- Reading a Periodic Table
 - Moles
 - Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
 
<u>Stoichiometry</u>  
- Using Dimensional Analysis
 - Analyzing reactions RxN
 
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] 6H₂ + O₂ → 3H₂O
[Given] 18 mol H₂
[Solve] mol H₂O
<u>Step 2: Identify Conversions</u>
[RxN] 6 mol H₂ → 3 mol H₂O
<u>Step 3: Stoich</u>
- [DA] Set up conversion:                                                                               

 - [DA] Simplify:                                                                                                 

 - [DA] Divide [Cancel out units]:                                                                     

 
 
        
                    
             
        
        
        
Answer:
Heating the system
Explanation:
According to the principle of Le Chatelier, for a system at equilibrium, a specific disturbance would make the equilibrium shift toward the direction which minimizes such a disturbance.
Since we wish to shift the equilibrium to the left, this means we wish to increase the concentration of products, as an excess in their concentration would make the products react and produce more reactants in order to lower the excess concentration of products.
Since heat is also a product, an increase in heat would shift the equilibrium toward the left, as this would consume the excess of heat by producing the reactants.
 
        
             
        
        
        
C = 4 mol/l
v = 0.5 l
n(NaCl)=cv
n(NaCl) = 4 mol/l · 0.5 l = 2 mol
2 moles of NaCl must be dissolved