Question

A sample of dangerously reactive fluorine gas is contained in a stainless steel container which has a 31 L capacity at a pressure of 160 pounds per square inch and a temperature of 26.0◦C. What mass of fluorine gas sample is in the stainless steel container? 1. 10.3098 g 2. 522.362 g 3. 6.87318 g 4. 27.4927 g 5. 18.3285 g

Answer 1

Answer:

The mass of fluorine gas sample  in the stainless steel container is

522.455 grams

Explanation:

To solve the question, we note the given parameters to see if we have enough facts to provide an answer

Volume of container = 31 L = 0.031 m³

Pressure of the fluorine in the container = 160 psi

Temperature of the fluorine gas in the container = 26 °C

We have the universal gas equation given by

P·V = n·R·T

Where P = Pressure 160 psi = ‪1103161‬ Pa

V = Volume = 31 L = 0.031 m³

n = Number of moles

T = Temperature = 26 °C = (273.15 + 26) K= 299.15 K and

R = Universal gas constant = 8.314 J/mol·K

Therefore n = $\frac{PV}{RT}$ = $\frac{1103161*0.031}{8.314*299.15}$ = 13.75 moles of fluorine

The molar mass of fluorine gas = 37.99681 g/mol

Therefore the mass of fluorine gas contained in the stainless steel container is 13.75 moles × 37.99681 g/mol = 522.455 grams