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guajiro [1.7K]
2 years ago
12

when acceleration is held constant and objects of different mass are observed,are mass and force directly proportional or invers

ely proportional?Explain.
Chemistry
1 answer:
svetoff [14.1K]2 years ago
5 0
Yes. When two things are directly prortional, that means that as one increases, the other increases at the same rate. So, say you have a 2kg object at an acceleration of 2m/s^2. The force would be 4N. If you have a 3kg object at an acceleration of 2m/s^2, the force would be 6N. If two things are inversely proportional, that means that as one thing increases the other decreases at the same rate. A good example of this is in a chemical reaction. If you increase the surface area of the reactants, the reaction time decreases. They are inversely proportional.
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Based on the ion structure, which of the following elements would form a bond with calcium in a one to one ratio and why?
blsea [12.9K]

Answer:

a

Explanation:

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5 0
2 years ago
Read 2 more answers
76/304=81/k what is K and show work plez
siniylev [52]
You can cross multiply and then get k alone so it would look like this:
76         81    
-----  =   ------    =  76k= 24624
304        k            -----  -----------  =      k  =  324
                             76        76


so k is equal to 324

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4 0
3 years ago
Help ASAP Iill mark you as brainlister
lions [1.4K]

C. Yes, if each sample contains 6.02 x 10²³ atoms.

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3 years ago
Rutherfordium-261 has a half-life of 1.08 min. How long will it take for a sample of rutherfordium to lose one-third of its nucl
Ira Lisetskai [31]

Answer:

t=1.712min

Explanation:

Hello!

In this case, since the radioactive decay equation is:

\frac{A}{A_0}=2^{-\frac{t}{t_{1/2} }

Whereas A stands for the remaining amount of this sample and A0 the initial one. In such a way, since the sample of rutherfordium is reduced to one-third of its nuclei, the following relationship is used:

A=\frac{1}{3} A_0

And we plug it in to get:

\frac{\frac{1}{3} A_0}{A_0}=2^{-\frac{t}{t_{1/2}} } \\\\\frac{1}{3}=2^{-\frac{t}{t_{1/2}} }

Now, as we know its half-life, we can compute the elapsed time for such loss:

log(\frac{1}{3})=log(2^{-\frac{t}{t_{1/2}} })\\\\log(\frac{1}{3})=-\frac{t}{t_{1/2}} }*log(2)

t=-\frac{log(\frac{1}{3})t_{1/2}}{log(2)} \\\\t=1.71min

Best regards!

8 0
2 years ago
Compare and contrast the way energy can transfer from one object to another.
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Answer:

<h3>Energy is transferred from the hotter object to the cooler one, and the difference in temperature between them decreases.</h3>

Explanation

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2 years ago
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