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4 years ago

7

Which situation would not cause the following equilibrium to shift to the right

1 answer:

Elis [28]4 years ago

3 0

If you’re talking about a reaction, an increase in the products (values on the right side of the chemical equation) would cause the reaction to shift left instead of right. Also a decrease in the reactants.

Also, could be wrong, but increasing the volume/ decreasing the pressure on the reactant side will cause the reaction to shift left

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a 40-lb container of peat moss measure 14x20x30 inches and has an average density of 0.13 g/cm^3. how many bags of peat moss are

telo118 [61]

Volume of the peat moss = $14\times 20\times 30 inches$

= $8400 in^{3}$

Convert the above volume into $cm^{3}$

$1 in^{3}= 16.4 cm^{3}$

Thus, volume in $cm^{3}$ is:

Volume of peat moss = $8400 in^{3}\times \frac{16.4 cm^{3}}{1 in^{3}}$

= $137760 cm^{3}$

Now,

Total volume by using area and depth of the peat moss = $area of peat moss \times depth of peat moss$

= $(13 ft \times 25 ft)\times 1.9 inches$

= $(325 ft^{2})\times 1.9 inches$

Convert above values in $cm$ to get the value of volume in $cm^{3}$ :

$1 ft= 30.48 cm$

$1 in= 2.54 cm$

Thus, volume in $cm^{3}$ is:

Total volume = $(325 ft^{2}\times\frac{(30.48 cm)^{2}}{(1 ft)^{2}})\times (1.9 in\times \frac{2.54 cm}{1 in})$

= $301934.88 cm^{2}\times 4.826 cm$

= $1457137.73088 cm^{3}$

Now, number of bags is calculated by the ratio of total volume of the peat moss to the volume of the peat moss.

$Number of bags =\frac{total volume of peat moss}{volume of peat moss}$

Substitute the values of volume in above formula:

$Number of bags = \frac{1457137.73088 cm^{3}}{137760 cm^{3}}$

= $10.57$

≅ $11$ bags

Thus, number of bags of peat moss are needed to cover an area measure $13 ft$ by $25 ft$ to a depth of $1.9 inches$ are $11$ bags.

4 0

3 years ago

A 35 gram of saturated solution is distilled out completely. If the solubility of the solute is 110, find the amount of residue

kipiarov [429]

Answer:

3850g

Explanation:

Solubility is the amount of solute dissolved in a solvent.

Solubility is mass of solute÷mass of solvent

The solvent is 35grams

Solute?

Solubility of solute is 110

110=x/35

= 110 × 35

The amount of residue solute is 3850g

8 0

3 years ago

Calculate the molarity of a solution consisting of 60.0 g of NaOH in 1.50 L of solution.

Trava [24]

Explanation:

here's the answer to your question

7 0

3 years ago

(b) The chemical equation for the reaction between lithium and oxygen is 4Li + 0,2L1,0 Write a chemical equation for the reactio

BabaBlast [244]

Answer:

Li3N

Explanation:

Li+N2=Li3N.........................

5 0

3 years ago

How many grams are there in 3.5 moles of H20

aksik [14]

Molar mass H₂O = 18.0 g/mol

1 mol ----- 18.0 g
3.5 moles --- ?

Mass ( H₂O) = 3.5 x 18.0 / 1

=> 63.0 g

hope this helps!

8 0

4 years ago