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SCORPION-xisa [38]
4 years ago
5

What happens when carbon dioxide at 74°C is placed in thermal contact with water at 14°C? Energy leaves the carbon dioxide and e

nters the water. The water gets hotter than the carbon dioxide. The temperatures of the two substances equalize. Both the water and the carbon dioxide decrease in temperature. The water stays colder than the carbon dioxide.
Chemistry
1 answer:
qaws [65]4 years ago
5 0
<h3><u>Answer;</u></h3>

The temperatures of the two substances equalize.

<h3><u>Explanation;</u></h3>
  • When two objects at different temperatures are placed in contact, heat flows from the warmer object to the cooler one until the temperature of both objects is the same.
  • <em><u>The amount of heat that flows from a warmer object is the same as the amount of heat that flows into a cooler object. Because the direction of heat flow is opposite for the two objects, the sign of the heat flow values must be opposite. </u></em>
  • <em><u>In line with the law of conservation of energy, the amount of heat lost by a warmer object equals the amount of heat gained by a cooler object. Therefore the amount of heat lost by carbon dioxide is equal to the amount of heat gained by water.</u></em>
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To begin, we need to change the grams to a percentage. We can simply take the number and call it our percentage. (i.e 0.262%)

Then, we have a simply stoichiometry step. We put our starting number over 1, as usual. The next "Step" is putting in the molar mass of that particular element on the bottom, with one on top. It should look like this: 

0.262% N          1
-------------- x ----------------      
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We would then divide those two numbers to get our answer. Repeat for the other elements included, until we have all of them done.

After that, we need to find the smallest number that was the answer to one of the equations. For example, if the product of Hydrogen was the smallest formed, we would locate that number. We then divide ALL of our answers by that smallest number.

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Then, we need to take those whole numbers we got for each number, and plug in to make a compound. For example, if our products were 6 for nitrogen, 3 for hydrogen, and 2 for chlorine, our final empirical formula would be N6H3Cl2.

Hope I could help! If it was a bit wordy please let me know and I'd be more than willing to clarify.   
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