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SCORPION-xisa [38]
4 years ago
5

What happens when carbon dioxide at 74°C is placed in thermal contact with water at 14°C? Energy leaves the carbon dioxide and e

nters the water. The water gets hotter than the carbon dioxide. The temperatures of the two substances equalize. Both the water and the carbon dioxide decrease in temperature. The water stays colder than the carbon dioxide.
Chemistry
1 answer:
qaws [65]4 years ago
5 0
<h3><u>Answer;</u></h3>

The temperatures of the two substances equalize.

<h3><u>Explanation;</u></h3>
  • When two objects at different temperatures are placed in contact, heat flows from the warmer object to the cooler one until the temperature of both objects is the same.
  • <em><u>The amount of heat that flows from a warmer object is the same as the amount of heat that flows into a cooler object. Because the direction of heat flow is opposite for the two objects, the sign of the heat flow values must be opposite. </u></em>
  • <em><u>In line with the law of conservation of energy, the amount of heat lost by a warmer object equals the amount of heat gained by a cooler object. Therefore the amount of heat lost by carbon dioxide is equal to the amount of heat gained by water.</u></em>
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Explanation:

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3 years ago
. Monthly measurements of atmospheric CO2 concentration at Mauna Loa began in March 1958. The average CO2 concentration for that
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Answer:

Increase=98.8ppm

Average\ increase/year=1.594\frac{ppm}{year}

Explanation:

Hello,

In this case, since the nowadays concentration of CO2 is 414.51 ppm and the concentration in 1958 was 315.71 ppm, the total increase is computed via the difference between them:

Increase=414.51ppm-315.71ppm\\\\Increase=98.8ppm

Moreover, the average increase per year is computed considering that from 1958 to 2020, 62 years have passed, therefore, such average is:

Average\ increase/year=\frac{98.8ppm}{62 years} \\\\Average\ increase/year=1.594\frac{ppm}{year}

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