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ra1l [238]
2 years ago
7

Pre calculate solver

Mathematics
1 answer:
egoroff_w [7]2 years ago
5 0
What is your question I will answer it if I can
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The area of a triangle with base 10in and height 4 in is<br> 20in^2<br> 40in^2<br> 15in^2<br> 60in^2
natta225 [31]

1/2(BH)

=1/2(10*4)

=1/2(40)

=20


5 0
3 years ago
Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact
umka2103 [35]

Solution:

The permutation formula is expressed as

\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\  \end{gathered}

The combination formula is expressed as

\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\  \\  \end{gathered}

where

\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}

Given that 6 objects are taken at a time from 8, this implies that

\begin{gathered} n=8 \\ r=6 \end{gathered}

Thus,

Number of permuations:

\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}

Number of combinations:

\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}

Hence, there are 28 combinations and 20160 permutations.

7 0
11 months ago
An interval has the notation (-6,-2). find the midpoint
notka56 [123]
<span>(6+8)/2 = 14/2 = 7 hope this helps

</span>
8 0
3 years ago
Read 2 more answers
What is m<br> A.55°<br> B.58°<br> C.122°<br> D.125°
Andreyy89

Answer: k = 55 degrees

Step-by-step explanation:

to find J, subtract 122 from 180, you get 58. The total number of degrees is 180. Since L is given as 67, and 67+58=125. Simply subtract 125 from 180 which is 55 degrees

5 0
3 years ago
Which statement proves that the diagonals of square PQRS are perpendicular bisectors of each other? The length of SP, PQ, RQ, an
MatroZZZ [7]

Answer: the correct answer is letter D, I just took the test and got it right on edg

8 0
3 years ago
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