4 years ago

What are the three types of protists? When is an organism classified as a protist?

Physics

1 answer:

borishaifa [10]4 years ago

7 0

Answer:

Protozoa, Algae and Fungus-like protists. And by how they obtain nutrition.

Explanation:

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Two electrons are separated by 1.70 nm. What is the magnitude of the electric force each electron exerts on the other?

lidiya [134]

Answer:

$F=7.96*10^{-11}N$

Explanation:

According to Coulomb's law, the magnitude of the electric force between two equals charges (q) is given by:

$F=\frac{kq^2}{d^2}$

Here k is the coulomb constant and d is the distance between the charges. For two electrons we have:

$F=\frac{ke^2}{d^2}\\F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-1.6*10^{-19}C)^2}{(1.7*10^{-9}m)^2}\\F=7.96*10^{-11}N$

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3 years ago

Wavelength multiplied by frequency equals

Kruka [31]

Wavelength × frequency = speed

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3 years ago

Suppose there was a star with a parallax angle of 1 arcsecond. How far away would it be?

jok3333 [9.3K]

Answer: 3.26 light years

Explanation:

Each star has a parallax of one arcsecond at a distance of one parsec, which is equivalent to 3.26 light years.

so the parallax of 1 arcsecond will be at a distance of <em>1/1 × 3.26 light years</em>

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4 years ago

Suppose that the mirror described in Part A is initially at rest a distance R away from the sun. What is the critical value of a

Sati [7]

Ans;

6.25m²/Kd

Explanation: see attached file

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3 years ago

A fully loaded, slow-moving freight elevator has a cab with a total mass of 1200 kg, which is required to travel upward 54 m in

Lana71 [14]

Answer:

The average power is calculated as 735.0 W

Solution:

As per the question:

Total mass, M = 1200 kg

Counter mass of the elevator, m = 950

Distance traveled by the elevator, d = 54 m

Time taken, t = 3 min = 180 s

Now,

To calculate the average power:

First, we find the force needed for lifting the weight:

Force, F = (M - m)g = $(1200 - 950)\times 9.8 = 2450 N$

Now, the work done by this force:

W = Fd = $2450\times 54 = 132300\ J = 132.3\ kJ$

Average power is given as:

$P_{avg} = \frac{W}{t} = \frac{132300}{180} = 735.0\ W$

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3 years ago