Part (a):
We know that:
1 kw = 1000 watt ..........> Therefore, to convert watt into kw, we will divide by 1000
1 hour = 60 min ..........> Therefore, to convert mins into hours, we will divide by 60
Based on the above, the conversion results for the two units together would be as follows:
1 watt minute is equivalent to <span>0.000017 kilowatt hours
</span>Now, for the given , we will simply use cross multiplication to do the conversion as follows:
1 watt minute..............> 0.000017 kilowatt hours
750*15 ................> ??
750*15 watt min = 0.19125 kilowatt hour
Part (b):
From part a, we have that the consumption is 0.19125 kilowatt hour per day. Assuming that the year is 365 days, we would have:
yearly consumption = 0.19125 * 365 = 69.80625 kilowatt hour
The cost is 8 cents/kilowatt hour
Therefore:
yearly cost = 69.80625 * 8 = 558.45 cents
Hope this helps :)
Answer:
younger than 50,000 years and older than 100 years
Explanation:
Carbon-14 is produced in the upper atmosphere when cosmic rays bombard nitrogen atoms. The ensuing atomic interactions create a steady supply of c14 that rapidly diffuses throughout the atmosphere. Plants take up c14 along with other carbon isotopes during photosynthesis in the proportions that occur in the atmosphere. animals acquire c14 by eating the plants (or other animals). During the lifetime of an organism, the amount of c14 in the tissues remains at an equilibrium since the loss (through radioactive decay) is balanced by the gain (through uptake via photosynthesis or consumption of organically fixed carbon). However, when the organism dies, the amount of c14 declines such that the longer the time since death the lower the levels of c14 in organic tissue. This is the clock that permits levels of c14 in organic archaeological, geological, and paleontological samples to be converted into an estimate of time.
half-life of radiocarbon is actually 5730 ± 40 years
<u>Since there are practical limits to the age range of the method, most samples must be younger than 50,000 years and older than 100 years.</u>
Answer:
Explanation:
We have given given the final angular velocity 
And 
Displacement 
We have to find the angular acceleration 
According to law of motion 
So 
In question we have tell about magnitude only so
The concepts used to solve this exercise are given through the calculation of distances (from the Moon to the earth and vice versa) as well as the gravitational potential energy.
By definition the gravitational potential energy is given by,
Where,
m = Mass of Moon
G = Gravitational Universal Constant
M = Mass of Ocean
r = Radius
First we calculate the mass through the ratio given by density.
PART A) Gravitational potential energy of the Moon–Pacific Ocean system when the Pacific is facing away from the Moon
Now we define the radius at the most distant point
Then the potential energy at this point would be,
PART B) when Earth has rotated so that the Pacific Ocean faces toward the Moon.
At the nearest point we perform the same as the previous process, we calculate the radius
The we calculate the Potential gravitational energy,
