3 years ago

the illuminance on a surface is 6 lux and the surface is 4 meters from the light source. What is the intensity of the saurce?

Physics

1 answer:

Lelechka [254]3 years ago

8 0

L = illuminance
A = surface
i = intensity

L = i / A ==: i = L * A

i = 6 lux * 4 m^2 = 24 lumen

You might be interested in

I didnt want my question public i made a mistake i want it taken down

mrs_skeptik [129]

Then report it and it might be taken down

5 0

3 years ago

represents the space-time, speed-time and acceleration-time graphs for a ball pulled upwards with a speed of 10 m / s from 1 met

alexandr1967 [171]

Gyhugugygubuhuhuhubu

5 0

3 years ago

A driver in a car traveling at a speed of 50 mi/h sees a deer 50 m away on the road. Calculate the minimum constant acceleration

alisha [4.7K]

Answer:

a= - 0.79 m/s²

Explanation:

Given that

Speed ,u = 20 mi/h

We know that

1 mi/h= 0.44 m/s

Therefore ,u = 8.94 m/s

Distance ,s= 50 m

Lets take the acceleration of the car = a m/s²

The final speed of the car ,v = 0 m/s

We know that

v²= u² + 2 a s

Now by putting the values

0²= 8.94² + 2 x a x 50

$a=-\dfrac{8.94^2}{2\times 50}\ m/s^2$

a= - 0.79 m/s²

Therefore the acceleration will be - 0.79 m/s².

6 0

3 years ago

An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above

Lilit [14]

The length of its image = $-3cm$

Given,

length of object, $h_o = 3 cm$

We know, for flat refracting surface,

Image distance = object distance

So,

magnification is = $-1$

length of the image,

$h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm$

Here, negative sign means inverted image.

For more information on refraction, visit

brainly.com/question/14760207?referrer=searchResults

3 0

3 years ago

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o

klio [65]

Answer:

The acceleration of Abbie is half of the Zak's.

Explanation:

The centripetal acceleration of an object on a circular path is given by :

$a=r\omega^2$

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Let $r_1$ is distance of Abbie from the merry-go-round and $r_2$ is distance of Zak's from the merry-go-round. Acceleration of Abbie is :

$a_1=r_1\omega^2$ ...... (1)

$r_1=1\ m$

Acceleration of Zak's is :

$a_2=r_2\omega^2$ .......(2)

$r_2=2\ m$

Dividing equation (1) and (2) we get :

$\dfrac{a_1}{a_2}=\dfrac{r_1}{r_2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{2}\\\\a_1=\dfrac{a_2}{2}$

So, the acceleration of Abbie is half of the Zak's.

7 0

3 years ago