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melisa1 [442]
3 years ago
7

What is co-ordinate covalent bond? why does such type of bonding arise?​

Chemistry
1 answer:
GenaCL600 [577]3 years ago
7 0

Explanation:

A coordinate covalent bond is a special type of covalent bond. In normal covalent bond, atoms combines and shares their electrons to form bonds.

  • In coordinate covalent bonds, two atoms are bonded in such a way that one member of the pair is supplying both electrons that are shared.
  • An atom supplies the lone pair of electrons to the other atom leaving net positive charge on the donor atom and negative charge on the acceptor.

Just like all interatomic bond types, coordinate covalent bond forms in order for atoms to attain stability through filling their outer energy levels like the noble gases. This is why atoms can share electrons, gain or lose electrons to reach this state.

Learn more:

Covalent bonds brainly.com/question/5258547

#learnwithBrainly

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How many liters of o2 do you have if you have 5.8 moles of o2
polet [3.4K]

Answer:

130 Liters

Explanation:

if 1 mol is 22.4 L, then 5.8 mol is 130 L (129.92 but use sig figs)

3 0
3 years ago
How many molecules are in 69 grams of Na?
12345 [234]
Molar mass Na = 23.0 g/mol

1 mol ---- 23.0 g
n mol ---- 69 g

n = 69 / 23.0

n = 3.0 moles

1 mole -------- 6.02x10²³ molecules
3.0 moles ---- ?

3.0 *  6.02x10²³ / 1

= 1.806x10²⁴ molecules

hope this helps!




7 0
3 years ago
Which of the following is not found in a nucleotide?
Firlakuza [10]

Amino acid is not found in a nucleotide.

8 0
3 years ago
How is helium different from other noble gases?
Slav-nsk [51]
Helium only possesses two valence electrons, while the other noble gasses posses eight
3 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
EleoNora [17]

Answer:

\large \boxed{\text{2.20 g Pb}}

Explanation:

They gave us the masses of two reactants and asked us to determine the mass of the product.

This looks like a limiting reactant problem.

1. Assemble the information

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ:       239.27   32.00        207.2

            2PbS   +   3O₂   ⟶  2Pb   +   2SO₃

m/g:      2.54        1.88

2. Calculate the moles of each reactant

\text{Moles of PbS} = \text{2.54 g PbS } \times \dfrac{\text{1 mol PbS}}{\text{239.27 g PbS}} = \text{0.010 62 mol PbS}\\\\\text{Moles of O}_{2} = \text{1.88 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.058 75 mol O}_{2}

3. Calculate the moles of Pb from each reactant

\textbf{From PbS:}\\\text{Moles of Pb} =  \text{0.010 62 mol PbS} \times \dfrac{\text{2 mol Pb}}{\text{2 mol PbS}} = \text{0.010 62 mol Pb}\\\\\textbf{From O}_{2}:\\\text{Moles of Pb} =\text{0.058 75 mol O}_{2} \times \dfrac{\text{2 mol Pb}}{\text{3 mol O}_{2}}= \text{0.039 17 mol  Pb}\\\\\text{PbS is the $\textbf{limiting reactant}$ because it gives fewer moles of Pb}

4. Calculate the mass of Pb

\text{ Mass of Pb} = \text{0.010 62 mol Pb} \times \dfrac{\text{207.2 g Pb}}{\text{1 mol Pb}} = \textbf{2.20 g Pb}\\\\\text{The reaction produces $\large \boxed{\textbf{2.20 g Pb}}$}

4 0
3 years ago
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