What is the weight of a 45 kg box in newtons

What is the concentration of the 100 g of solution having 25 g of solute?

Alexus [3.1K]

Answer:

70%

Explanation:

it's 70% hope it helps

8 0

2 years ago

A tightly wound toroid of inner radius 1.2 cm and outer radius 2.4 cm has 960 turns of wire and carries a current of 2.5 A.

OLEGan [10]

Answer:

a

$B = 0.0533 \ T$

b

$B = 0.04 \ T$

Explanation:

From the question we are told that

The inner radius is $r = 1.2 \ cm = 0.012 \ m$

The outer radius is $r_o = 2.4 \ cm = \frac{2.4}{100} = 0.024 \ m$

The nu umber of turns is $N = 960$

The current it is carrying is $I = 2. 5 A$

Generally the magnetic field is mathematically represented as

$B = \frac{\mu_o * N* I }{2 * \pi * r }$

Where $\mu_o$ is the permeability of free space with a constant value

$\mu = 4\pi * 10^{-7} N/A^2$

And the given distance where the magnetic field is felt is r = 0.9 cm = 0.009 m

Now substituting values

$B = \frac{ 4\pi * 10^{-7} * 960* 2.5 }{2 * 3.142 * 0.009 }$

$B = 0.0533 \ T$

Fro the second question the distance of the position considered from the center is r = 1.2 cm = 0.012 m

So the magnetic field is

$B = \frac{ 4\pi * 10^{-7} * 960* 2.5 }{2 * 3.142 * 0.012 }$

$B = 0.04 \ T$

6 0

3 years ago

The differential equation below models the temperature of an 88°C cup of coffee in a 24°C room, where it is known that the coffe

densk [106]

Answer:

$y = 24+64\cdot e^{-150\cdot t}$

Explanation:

Let solve the differential equation by separating corresponding variables:

$\int\limits^t_0\, dt = -\frac{1}{150} \int\limits^y_{y_{o}} \frac{dy}{y-24}$

The solution of this equation is:

$t = -\frac{1}{150}\cdot (\ln|y-24|-\ln |y_{o}-24|)$

The explicit form of the temperature as a function of time is:

$\ln |y-24|=-150\cdot t + \ln |y_{o}-24|$

$y-24 = C\cdot e^{-150\cdot t}$

The value of the integration constant is:

$C = 64$

The complete expression is:

$y = 24+64\cdot e^{-150\cdot t}$

3 0

3 years ago

A package is dropped from a helicopter that is descending steadily at a speed v0. After t seconds have elapsed, consider the fol

qaws [65]

Answer:

Part a)

$v = \sqrt{v_o^2 + g^2t^2}$

Part b)

$d = \frac{1}{2}gt^2$

Part c)

$v_f = v_o - gt$

Part d)

$d = \frac{1}{2}gt^2$

Explanation:

Part a)

As we know that speed of package is same as that of helicopter in horizontal direction

So after time "t" the velocity in x direction will remain constant while in Y direction it will go free fall

So we have

$v_y = -gt$

$v = \sqrt{v_x^2 + v_y^2}$

$v = \sqrt{v_o^2 + g^2t^2}$

Part b)

Distance from helicopter is same as the distance of free fall

so we will have

$d = \frac{1}{2}gt^2$

Part c)

If helicopter is rising upwards with uniform speed

then final speed of the package after time t is given as

$v_f = v_i + at$

$v_f = v_o - gt$

Part d)

distance from helicopter

$d = \frac{1}{2}gt^2$

8 0

4 years ago

Read 2 more answers

If a rock is dropped from the top of a tower at the front of and it takes 3.6 seconds to hit the ground. Calculate the final vel

KengaRu [80]

Answer:

36 m/s

Explanation:

t = 3.6s

u = 0m/s

a = +g = 10m/s²

v = ?

using,

v = u + at

v = 0 + 10(3.6)

v = 36 m/s

7 0

3 years ago