If a rock is dropped from the top of a tower at the front of and it takes 3.6 seconds to hit the ground. Calculate the final vel
1 answer:
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Answer:
7.5 m/s
Explanation:
We can find its velocity when it reaches the buoy by applying one of Newton's equations of motion:
where v = final velocity
u = initial velocity
a = acceleration
s = distance traveled
From the question:
u = 28 m/s
a = -4
s = 91 m
Therefore:
The velocity of the boat when it reaches the buoy is 7.5 m/s.
Answer:
The jumper is in freefall for 12.447 seconds.
Explanation:
Let's start by calculating how far the jumper falls.
Initial height (on cliff) = 910 m
Final height after freefall = 150 m
Distance the jumper falls in freefall = 910 - 150 = 760 m
We can now use the equation of motion below to solve for the time:
here. acceleration = 9.81 m/s (due to gravity)
initial speed (u) = 0 m/s (because vertical speed is 0 at the start)
and distance (s) = 760 meters (as calculated above)
So for speed we get:
t = 12.447 seconds