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miv72 [106K]
2 years ago
13

Does the surface tension of water affect the rate of evaporation? If so, would adding a surfactant speed up evaporation?

Physics
1 answer:
Goshia [24]2 years ago
6 0

Answer:

The evaporation time gradually increased with the increase in surfactant concentration, i.e., from water to the concentration level of 0.005%. Furthermore, the evaporation time is significantly reduced, even lower than that of water containing relatively high concentrations from 0.01% to 0.1%.

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How do weathering process affect deserts?
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Water and wind cause mechanical weathering and produce angular rocks, sheer canyon walls, and pebble-covered surfaces.
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3 years ago
A fisherman noticed that a wave strikes the boat side every 5 seconds. The distance between two consecutive crest is 1.5m. What
GrogVix [38]
5/1.5=7 I think that is the answer
8 0
3 years ago
At what speed does a typical electron pass by any given point in the wire?
attashe74 [19]
A 5.00 A current runs through a 12 gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5*10^28 free electrons per cubic metre.

a) How many electrons pass through the light bulb each second?

b) What is the current density in the wire? (answer in A/m^2)

<span>c) At what speed does a typical electron pass by any given point in the wire? (answer in m/s)

</span>a) 5.0 A = 5.0 C/s 
. Number of electrons in 5.0C = 5.0 / 1.60^-19 = 3.125^19
. 5.0 A ►= 3.125^19 electrons/s

b) A/m² = 5.0 / π(1.025^-3 m)² .. .. ►= 1.52^6 A/m²

c) Charge density (q/m³) = 8.50^28 e/m³ x 1.60^-19 = 1.36^10 C/m³

(q/m³)(m²)(m/s) = q/s (current i in C/s [A])
(m²) = Area
(m/s) = mean drift speed

(q/m³)(A)(v) = i

v = i.[(q/m³)A]ˉ¹

<span>v = 5.0 [1.36^10 * π(1.025^-3 m)²]ˉ¹.. .. ►v = 1.10^-4 m/s</span>
7 0
3 years ago
Explain how the pressure at the bottom of a container depends on the container shape and the fluid height
3241004551 [841]

The pressure at the bottom of a column of fluid in a container
depends only on the depth of the fluid, not on the shape of the
container.  The pressure is simply the result of the weight of the
fluid resting on the bottom.

3 0
3 years ago
A baseball is thrown at an angle of 20° relative to the ground at a speed of 25 m/s if the ball was caught 50 m from the thrower
scoray [572]

Answer:

2.1 s

Explanation:

The motion of the ball is a projectile motion. We know that the horizontal range of the ball is

d = 50 m

And that the initial speed of the ball is

u=25 m/s

at an angle of

\theta=20^{\circ}

So, the horizontal speed of the ball (which is constant during the entire motion) is

u_x = u cos \theta = 25 \cdot cos 20^{\circ} = 23.5 m/s

And since the horizontal range is 50 m, the time taken for the ball to cover this distance was

t=\frac{d}{u_x}=\frac{50}{23.5}=2.1 s

which is the time the ball spent in air.

8 0
2 years ago
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