It's lead. That's why the "apron" is so heavy.
The Electric field is zero at a distance 2.492 cm from the origin.
Let A be point where the charge
C is placed which is the origin.
Let B be the point where the charge
C is placed. Given that B is at a distance 1 cm from the origin.
Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.
i.e., at distance 'x' from B.
Using Coulomb's law,
,
= ![15\times 10^-6 C](https://tex.z-dn.net/?f=15%5Ctimes%2010%5E-6%20C)
![Q_B=9\times10^-6C](https://tex.z-dn.net/?f=Q_B%3D9%5Ctimes10%5E-6C)
![d_A = 1+x cm](https://tex.z-dn.net/?f=d_A%20%3D%201%2Bx%20cm)
![d_B=x cm](https://tex.z-dn.net/?f=d_B%3Dx%20cm)
k is the Coulomb's law constant.
On substituting the values into the above equation, we get,
![\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%2815%5Ctimes10%5E-6%29%5E2%7D%7B%281%2Bx%29%5E2%7D%20%3D%5Cfrac%7B%289%5Ctimes10%5E-6%29%5E2%7D%7Bx%5E2%7D)
Taking square roots on both sides and simplifying and solving for x, we get,
1.67x = 1+x
Therefore, x = 1.492 cm
Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.
Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926
#SPJ4
-1- was created in the 1600 by william gilbert
-2-When the charge is positive, electrons in the metal of the electroscope are attracted to the charge and move upward out of the leaves. This results in the leaves to have a temporary positive charge and because like charges repel, the leaves separate. When the charge is removed, the electrons return to their original positions and the leaves relax
3-
An electroscope is made up of a metal detector knob on top which is connected to a pair of metal leaves hanging from the bottom of the connecting rod. When no charge is present the metals leaves hang loosely downward. But, when an object with a charge is brought near an electroscope, one of the two things can happen.
When an object moves its length contracts in the direction of motion. The faster it moves the shorter it gets in the direction of motion.
The object in this question moves and then stops moving. So it's length first contracts and then expands to its original length when the motion stops.
The speed doesn't have to be anywhere near the speed of light. When the object moves its length contracts no matter how fast or slow it's moving.